计算机处理的各种数据类型都有个范围,超出范围的就处理不了. 如果做超大数运算加减乘除,普通方法肯定是不行的,那么我们遇到大数的运算怎么处理呢?今天介绍一种大数加减乘除运算的方法 思路: 1. 将两个特大的整数利用字符数组作为存储介质. 2. 逐位计算 遍历结果逢十进一. 3. 对存储结果的数组进行翻转处理. 下面上代码: public class LargeIntSub { public static void main(String[] args) { String a="6789"…

A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 230395    Accepted Submission(s): 44208 Problem Description I have a very simple problem for you. Given two integers A and B, you…

字串数 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2661    Accepted Submission(s): 606 Problem Description 一个A和两个B一共可以组成三种字符串:"ABB","BAB","BBA". 给定若干字母和它们相应的个数,计算一共可以组…

两个字符串表示两个非常大的数,请设计算法计算这两个大数的乘积,结果用字符串表示.例如S1="7832974972840919321747983209327",S2="1987432091904327543957",设计算法计算出S1*S2的结果,结果用String输出,不准用BigInter. 思路: 根据手工计算两数相乘的过程,用代码实现这个过程. 代码: import java.util.Scanner; public class DaZhengShuCheng…

大明A+B Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8483 Accepted Submission(s): 3000 Problem Description 话说,经过了漫长的一个多月,小明已经成长了许多,所以他改了一个名字叫“大明”.这时他已经不是那个只会做100以内加法的那个“小明”了,现在他甚至会任意长度的正小数的加法. 现在,…

Train Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5372    Accepted Submission(s): 2911 Problem Description As we all know the Train Problem I, the boss of the Ignatius Train Stati…

问题: 大数相加不能直接使用基本的int类型,因为int可以表示的整数有限,不能满足大数的要求.可以使用字符串来表示大数,模拟大数相加的过程. 思路: 1.反转两个字符串,便于从低位到高位相加和最高位的进位导致和的位数增加: 2.对齐两个字符串,即短字符串的高位用‘0’补齐,便于后面的相加: 3.把两个正整数相加,一位一位的加并加上进位. 具体代码如下: /** * 用字符串模拟两个大数相加 * @param n1 加数1 * @param n2 加数2 * @return 相加结果 */ pu…

代码: import java.math.*; import java.util.Scanner; public class Main { public static void main(String args[]){ Scanner cin = new Scanner(System.in); BigInteger sum,a; sum = BigInteger.valueOf(0); while(true){ a = cin.nextBigInteger(); if(a.equals(BigI…

先贴上代码 public String multiply(String num1, String num2) { String str = ""; StringBuffer sb = new StringBuffer(num1); num1 = sb.reverse().toString(); sb = new StringBuffer(num2); num2 = sb.reverse().toString(); int[] res = new int[num1.length() +…

Description Jiajia and Wind have a very cute daughter called Autumn. She is so clever that she can do integer additions when she was just 2 years old! Since a lot of people suspect that Autumn may make mistakes, please write a program to prove that A…