CF11D-A Simple Task【状压dp】】的更多相关文章

传送门 \(N \leq 19\)-- 不难想到一个状压:设\(f_{i,j,k}\)表示开头为\(i\).结尾为\(j\).经过的点数二进制下为\(k\)的简单路总数,贡献答案就看\(i,j\)之间有没有边. 当然,会有一些问题:①路会算重:②\(2^NN^2\)的数组开不下(当然②才是重点),所以考虑优化算法 考虑类似最小环的优化 设\(f_{i,j}\)表示开头为\(log_2lowbit(j)\),结尾为\(i\),经过的点数二进制下为\(j\)的简单路总数,转移跟上面类似,值得注意的是…
\(solution:\) 思路大家应该都懂: 状压DP:\(f[i][j]\),其中 \(i\) 这一维是需要状压的,用来记录19个节点每一个是否已经走过(走过为 \(1\) ,没走为 \(0\) ,用 \(2\)进制 压缩一下即可).同时,我们认为状压中已经走过的序号最小的节点为出发节点,\(j\) 即数组第二维是路径终点.(当这两个数相同时,说明找到了一个环). 注:这种方法因为无向图的存在,会出现(同一条路径出现两次)(一条边和两个端点构成非法环)的情况,这只需要在输出答案时 \(ans…
Simple String Problem Recently, you have found your interest in string theory. Here is an interesting question about strings. You are given a string S of length n consisting of the first k lowercase letters. You are required to find two non-empty sub…
FZU - 2218Simple String Problem 题目大意:给一个长度为n含有k个不同字母的串,从中挑选出两个连续的子串,要求两个子串中含有不同的字符,问这样的两个子串长度乘积最大是多少? 根据题目所给的k<=16很自然的想到用状压dp来处理,但不知道该dp个什么,在观摩大佬的做法后才明白.我们用0000000000000000到1111111111111111表示pomnlkjhgfedcba的字符存不存在的状态,某个字符存在的话对应位就是1,反之就是0.一开始dp[x]就表示,…
http://codeforces.com/gym/100405 D题 题在pdf里 codeforces.com/gym/100405/attachments/download/2331/20132014-acmicpc-northwestern-european-regional-contest-nwerc-13-en.pdf D - Diagrams & TableauxA Young diagram is an arrangement of boxes in rows and colum…
G - Simple String Problem Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice FZU 2218 Description Recently, you have found your interest in string theory. Here is an interesting question about strings.…
题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5816 Description Hearthstone is an online collectible card game from Blizzard Entertainment. Strategies and luck are the most important factors in this game. When you suffer a desperate situation an…
1087: [SCOI2005]互不侵犯King Time Limit: 10 Sec Memory Limit: 162 MB Submit: 2337 Solved: 1366 [Submit][Status][Discuss] Description 在N×N的棋盘里面放K个国王,使他们互不攻击,共有多少种摆放方案.国王能攻击到它上下左右,以及左上左下右上右下八个方向上附近的各一个格子,共8个格子. Input 只有一行,包含两个数N,K ( 1 <=N <=9, 0 <= K &…
题目链接: 题目 D. Kefa and Dishes time limit per test:2 seconds memory limit per test:256 megabytes 问题描述 When Kefa came to the restaurant and sat at a table, the waiter immediately brought him the menu. There were n dishes. Kefa knows that he needs exactly…
Clear All of Them I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 122768/62768 K (Java/Others)Total Submission(s): 1455    Accepted Submission(s): 484 Problem Description Acmers have been the Earth Protector against the evil enemy for a lon…