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Objections are healthy. When someone is being offered a new opportunity or product, it's not unusual for there to be objections. These are issues, the missing feature or unwanted element that's keeping us from saying, "yes." On the other hand, a…
哈哈,虽然是一道字符串水题,可是拿到一个1A还是很开心的! 题意就是给一些keywords(子串)和Excuse(母串),然后输出包含keywords最多的Excuse,如果相等的话,按任意顺序全部输出即可. 解题时有几点需要注意: 1.一个keyword可能在Excuse里重复多次. 2.每个keyword的左右两端必须是行首或行尾或不是字母的字符. 3.Excuse里貌似是不区分大小写的,所以读入所有的Excuse后需要再memcpy一份,把那份用来全部转化为大写或小写,原来的那份作输出用.…
Description Judge Ito is having a problem with people subpoenaed for jury duty giving rather lame excuses in order to avoid serving. In order to reduce the amount of time required listening to goofy excuses, Judge Ito has asked that you write a progr…
Judge Ito is having a problem with people subpoenaed for jury duty giving rather lame excuses in order to avoid serving. In order to reduce the amount of time required listening to goofy excuses, Judge Ito has asked that you write a program that will…
解题报告 题意: 找包括单词最多的串.有多个按顺序输出 思路: 字典树爆. #include <cstdio> #include <cstring> #include <iostream> using namespace std; int k,e,num[100],cnt; struct node { int v; node *next[26]; }; node *newnode() { node *p=new node; p->v=0; int i; for(i…
简单字符串. #include <cstdio> #include <cstring> #define MAXLEN 105 #define MAXN 25 char keys[MAXN][MAXN]; char lines[MAXN][MAXLEN]; int nums[MAXN]; int main() { ; int n, m, max; int i, j, k, v; char tmp[MAXLEN]; while (scanf("%d %d",&…
The Sorrows of Young Werther J.W. von Goethe Thomas Carlyle and R.D. Boylan Edited by Nathen HaskellDole PREFACE I have carefully collected whatever I have been able to learnof the story of poor Werther, and here present it to you , knowing thatyou w…
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Dec. 31, 2015 Stayed up to last minute of 2015, 12:00am, watching a few of videos about top 10 rules for success, and then, think about putting together a blog to share, for a successful year 2016. Top 10 rules for success 1. Jessica Alba2. Oprah Win…
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