LeetCode 838. Push Dominoes】的更多相关文章

原题链接在这里:https://leetcode.com/problems/push-dominoes/ 题目: There are N dominoes in a line, and we place each domino vertically upright. In the beginning, we simultaneously push some of the dominoes either to the left or to the right. After each second,…
[LeetCode]838. Push Dominoes 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/push-dominoes/description/ 题目描述: There are N dominoes in a line, and we place each domino vertical…
Push Dominoes There are N dominoes in a line, and we place each domino vertically upright. In the beginning, we simultaneously push some of the dominoes either to the left or to the right. After each second, each domino that is falling to the left pu…
题目如下: 解题思路:本题题目中有一点要求很关键,“we will consider that a falling domino expends no additional force to a falling or already fallen domino.”,正好对应题目中的例子2,要好好理解一下.因为输入的最大dominoes是10^5,所以要考虑性能问题.dominoes有三种状态:'R','L','.'.在最终状态里面,R和L是不会变的,只有'.'的状态可能会变成三种状态的任意一种.…
There are N dominoes in a line, and we place each domino vertically upright. In the beginning, we simultaneously push some of the dominoes either to the left or to the right. After each second, each domino that is falling to the left pushes the adjac…
There are N dominoes in a line, and we place each domino vertically upright. In the beginning, we simultaneously push some of the dominoes either to the left or to the right. After each second, each domino that is falling to the left pushes the adjac…
There are N dominoes in a line, and we place each domino vertically upright. In the beginning, we simultaneously push some of the dominoes either to the left or to the right. After each second, each domino that is falling to the left pushes the adjac…
838. 推多米诺 一行中有 N 张多米诺骨牌,我们将每张多米诺骨牌垂直竖立. 在开始时,我们同时把一些多米诺骨牌向左或向右推. 每过一秒,倒向左边的多米诺骨牌会推动其左侧相邻的多米诺骨牌. 同样地,倒向右边的多米诺骨牌也会推动竖立在其右侧的相邻多米诺骨牌. 如果同时有多米诺骨牌落在一张垂直竖立的多米诺骨牌的两边,由于受力平衡, 该骨牌仍然保持不变. 就这个问题而言,我们会认为正在下降的多米诺骨牌不会对其它正在下降或已经下降的多米诺骨牌施加额外的力. 给定表示初始状态的字符串 "S"…
我发现我非常不擅长解决这种 ummm充满了各种逻辑判断的问题 orz! 因为总是漏少几种情况(很绝望orz) 这道题我是这么判断的 temp为更改后的字符串,dominoes为原字符串 对于原字符串,只需要改变“.”的状态就好了 设置两个指针 low,high 扫描到当前字符“.”时,low从“.”左边往前扫,high从“.”右边往后扫 存在以前几种情况 1. dominoes[high]=='L'&&dominoes[low]!='R' 需要将“.”变为“L” 2.dominoes[lo…
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请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
[600] Non-negative Integers without Consecutive Ones [629] K Inverse Pairs Array [638] Shopping Offers [639] Decode Ways II [646] Maximum Length of Pair Chain [647] Palindromic Substrings 给定一个字符串,判断有多少子串是 palindromic 的,子串就算所有字母都相同,但是开始和结束位置的下标不同,也算不同…
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作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…
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