索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 038. Count and Say (Easy) 链接: 题目:https://leetcode.com/problems/Count-and-Say/ 代码(github):https://github.com/illuz/leetcode 题意: 数数.第一个是 1,第二个是数前一个数:1 个 1,就是 11…
Count the number of prime numbers less than a non-negative number, n 思路:数质数的个数 开始写了个蛮力的,存储已有质数,判断新数字是否可以整除已有质数.然后妥妥的超时了(⊙v⊙). 看提示,发现有个Eratosthenes算法找质数的,说白了就是给所有的数字一个标记,把质数的整数倍标为false,那么下一个没被标为false的数字就是下一个质数. int countPrimes(int n) { ) ; bool * mark…
The count-and-say sequence is the sequence of integers beginning as follows: 1, 11, 21, 1211, 111221, ... 1 is read off as "one 1" or 11. 11 is read off as "two 1s" or 21. 21 is read off as "one 2, then one 1" or 1211. Given…
题目要求:Count and Say The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ... 1 is read off as "one 1" or 11.11 is read off as "two 1s" or 21.21 is read off as "one 2, then one 1"…
leetcode - 35. Search Insert Position - Easy descrition Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the arr…
[LeetCode]120. Triangle 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址https://leetcode.com/problems/triangle/description/ 题目描述: Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjac…
1 导引 我们在博客<Hadoop: 单词计数(Word Count)的MapReduce实现 >中学习了如何用Hadoop-MapReduce实现单词计数,现在我们来看如何用Spark来实现同样的功能. 2. Spark的MapReudce原理 Spark框架也是MapReduce-like模型,采用"分治-聚合"策略来对数据分布进行分布并行处理.不过该框架相比Hadoop-MapReduce,具有以下两个特点: 对大数据处理框架的输入/输出,中间数据进行建模,将这些数据…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 素数筛法 参考资料 日期 [LeetCode] 题目地址:https://leetcode.com/problems/count-primes/ Total Accepted: 36655 Total Submissions: 172606 Difficulty: Easy 题目描述 Count the number of prime numbers…
The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ... 1 is read off as "one 1" or 11.11 is read off as "two 1s" or 21.21 is read off as "one 2, then one 1" or 1211. Given an…
Description: Count the number of prime numbers less than a non-negative number, n. Credits:Special thanks to @mithmatt for adding this problem and creating all test cases. 解析:大于1的自然数,该自然数能被1和它本身整除,那么该自然数称为素数. 方法一:暴力破解,时间复杂度为O(N^2) 代码如下: public class…