Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1:          Input: 121            Output: true Example 2:          Input: -121          Output: false                Explanat…
Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using ext…
Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: From left to right, it reads -121. From right to…
Problem: Determine whether an integer is a palindrome. Do this without extra space. 简单的回文数,大一肯定有要求写过,不过从基础开始尝试吧. Solution: public class Solution { public boolean isPalindrome(int x) { int n=1; int copyx=x; if(x<0)return false; if(x<10)return true; w…
这道题是LeetCode里的第9道题. 题目说的: 判断一个整数是否是回文数.回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数. 示例 1: 输入: 121 输出: true 示例 2: 输入: -121 输出: false 解释: 从左向右读, 为 -121 . 从右向左读, 为 121- .因此它不是一个回文数. 示例 3: 输入: 10 输出: false 解释: 从右向左读, 为 01 .因此它不是一个回文数. 进阶: 你能不将整数转为字符串来解决这个问题吗? 这道题虽然简单…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:回文数,回文,题解,Leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 判断回文字符串 翻转数字 日期 题目地址:https://leetcode.com/problems/palindrome-number/#/description 题目描述 Determine whether an integer is…
Find the smallest prime palindrome greater than or equal to N. Recall that a number is prime if it's only divisors are 1 and itself, and it is greater than 1.  For example, 2,3,5,7,11 and 13 are primes. Recall that a number is a palindrome if it read…
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example, "A man, a plan, a canal: Panama" is a palindrome. "race a car" is not a palindrome. Note: Have you consider that…
class Solution { public: bool isPalindrome(string s) { if(s=="") return true; ) return true; //单个字符,对称 char *p,*q; p=&s[]; //p指向开头 q=&s[s.length()-]; //q指向末尾 while(p!=q){ //测试字符串里是否有字母或数字,若没有,则立刻返回 '&&*p<'A') || (*p>'Z'&…
Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using ext…
描述:Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space. You could a…
Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation. For example: Given "aacecaaa", return "aaacecaaa&qu…
Given a string, determine if a permutation of the string could form a palindrome. Example 1: Input: "code" Output: false Example 2: Input: "aab" Output: true Example 3: Input: "carerac" Output: true Hint: Consider the palindr…
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A man, a plan, a canal: Panama"is a palindrome."race a car"is not a palindrome. Note: Have you consider that the…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: Input: "aab" Output: [ ["aa","b"], ["a","a","b"…
判断一个数字是否是回文数,尝试不用其他额外空间. 注意: 负数也有可能成为回文数吗? 如果你想让int转为string,注意不用其他空间这个约束. 你也可以翻转一个int,但是有可能会溢出.     public class Solution { public boolean isPalindrome(int x) { if(x<0) return false; int temp = x, reverseX = 0; while (temp > 0) { reverseX = reverseX…
题目: Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space. You could…
[抄题]: Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: From left to right, it reads -121. From ri…
Long Time No See !   题目链接https://leetcode.com/problems/palindrome-number/?tab=Description   首先确定该数字的位数.按照已知数字x对10进行多次求余运算,可以得到数字位数. 具体思路: 1.每次取出该数字的最高位和最低位进行比较. 2.如果不相等则直接返回FALSE, 3.如果相等修改x的值(去掉最高位也同时去掉最低位)其中去掉最高位可以通过求模运算,去掉最低位可以采用除以10 4.进行循环直到x的值不大于…
我现在在做一个叫<leetbook>的开源书项目,把解题思路都同步更新到github上了,需要的同学可以去看看 地址:https://github.com/hk029/leetcode 这个是书的地址:https://hk029.gitbooks.io/leetbook/ 009. Palindrome Number[E] 问题: Determine whether an integer is a palindrome. Do this without extra space. 思路 这里说不…
Determine whether an integer is a palindrome. Do this without extra space. 题目标签:Math 题目给了我们一个int x, 让我们判断它是不是回文数字. 首先,负数就不是回文数字,因为有个负号. 剩下的都是正数,只要把数字 reverse 一下,和原来的比较,一样就是回文. 当有overflow 的时候,返回一个负数就可以了(因为负数肯定不会和正数相等). Java Solution: Runtime beats 61.…
Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using ext…
Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: From left to right, it reads -121. From right to…
总时间限制:1000ms 内存限制: 65536kB 描述 给出一系列非负整数,判断是否是一个回文数.回文数指的是正着写和倒着写相等的数. 输入 一行,一个01字符串. 输出 若干行,每行是一个非负整数(不超过99999999) 样例输入 11 123 0 14277241 67945497 样例输出 YES NO YES YES NO ps.这个题是若干行输入... 题目链接 ac代码 /* @File : palidrome.cpp @Time : 2020/03/25 09:47:24 @…
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A man, a plan, a canal: Panama" is a palindrome."race a car" is not a palindrome. Note:Have you consider that th…
写一个方法,让"1234"变成回文数字“1234321”,就是顺着读和倒着读都是一样的:注:不让用reverse()方法: function palindrome(str){ var arr = str.split(""); var arr1 = [];  for (var i = arr.length - 1; i >= 0; i--) { arr1.push(arr[i]);}var arr2=arr.concat(arr1);var index=arr2…
一.题目链接:https://leetcode.com/problems/palindrome-number/ 二.题目大意: 给定一个整数,判断它是否为一个回文数.(例如-12,它就不是一个回文数:11它是一个回文数) 三.题解: 这道题目我一共用了两种解法: 方法1:将数字转化成字符串,然后首尾对应判断每个字符即可,代码如下: class Solution { public: bool isPalindrome(int x) { bool rs = true; stringstream ss…
Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space. You could also…
题目:一个5位数,判断它是不是回文数.即12321是回文数,个位与万位相同,十位与千位相同. 下面是代码: package test; public class BackNum { public static void main(String [] args){ BackNum demo = new BackNum(); System.out.println(demo.checkNum(123454321)); } public String checkNum(long number){ Str…
Leetcode(9)回文数 [题目表述]: 判断一个整数是否是回文数.回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数. 第一次:直接全部转 执行用时:148 ms: 内存消耗:13.4MB 效果:还行 class Solution: def isPalindrome(self, x: int) -> bool: s=str(x) if s==s[::-1]: return True else: return False 第二种方法:反转一半数字 执行用时:156 ms: 内存消耗…