Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. You will have direct access to the node but not to the root of the tree.…
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. 这道题让我们求二叉搜索树的某个节点的中序后继节点,那么我们根据BST的性质知道其中序遍历的结果是有序的, 是我最先用的方法是用迭代的中序遍历方法,然后用…
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. Example 1: Input: root = [2,1,3], p = 1 Output: 2 Explanation: 1's in-or…
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. Example 1: Input: root = [2,1,3], p = 1 Output: 2 Explanation: 1's in-or…
一般来说,删除节点可分为两个步骤: 首先找到需要删除的节点: 如果找到了,删除它. 说明: 要求算法时间复杂度为 O(h),h 为树的高度. 示例: root = [5,3,6,2,4,null,7] key = 3 5 / \ 3 6 / \ \ 2 4 7 给定需要删除的节点值是 3,所以我们首先找到 3 这个节点,然后删除它. 一个正确的答案是 [5,4,6,2,null,null,7], 如下图所示. 5 / \ 4 6 / \ 2 7 另一个正确答案是 [5,2,6,null,4,nu…
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…
450. 删除二叉搜索树中的节点 给定一个二叉搜索树的根节点 root 和一个值 key,删除二叉搜索树中的 key 对应的节点,并保证二叉搜索树的性质不变.返回二叉搜索树(有可能被更新)的根节点的引用. 一般来说,删除节点可分为两个步骤: 首先找到需要删除的节点: 如果找到了,删除它. 说明: 要求算法时间复杂度为 O(h),h 为树的高度. 示例: root = [5,3,6,2,4,null,7] key = 3 5 / \ 3 6 / \ \ 2 4 7 给定需要删除的节点值是 3,所以…
230. 二叉搜索树中第K小的元素 题目链接 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/kth-smallest-element-in-a-bst 著作权归领扣网络所有.商业转载请联系官方授权,非商业转载请注明出处. 题目描述 给定一个二叉搜索树的根节点 root ,和一个整数 k ,请你设计一个算法查找其中第 k 个最小元素(从 1 开始计数). 示例 1: 输入:root = [3,1,4,null,2], k = 1 输出:1…
原题链接在这里:https://leetcode.com/problems/inorder-successor-in-bst/ Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. Show Company…
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…