amazing #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define R(a,b,c) for(register int a = (b); a <= (c); ++ a) #define nR(a,b,c) for(register int a = (b); a >= (c); --…

题目描述 Bessie likes downloading games to play on her cell phone, even though she does find the small touch  screen rather cumbersome to use with her large hooves.She is particularly intrigued by the current g ame she is playing. The game starts with a…

4580: [Usaco2016 Open]248 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 255  Solved: 204[Submit][Status][Discuss] Description Bessie likes downloading games to play on her cell phone, even though she does find the small touch  screen rather cumbers…

n<=248个数字,可以进行这样的操作:将相邻两个相同的数字合并成这个数字+1,求最大能合成多少. f(i,j)--区间i到j能合成的最大值,f(i,j)=max(f(i,k)+1),f(i,k)=f(k+1,j). #include<stdio.h> #include<string.h> #include<algorithm> #include<stdlib.h> #include<math.h> //#include<iostre…

Description Bessie likes downloading games to play on her cell phone, even though she does find the small touch  screen rather cumbersome to use with her large hooves.She is particularly intrigued by the current g ame she is playing. The game starts…

Description 一个序列,每次可以把相邻的两个数合为一个,价值+1,求最后的最大价值. Sol 区间DP. \(f[i][j]\) 表示 \(i-j\) 中合成一个数字为多少,转移就是枚举断点,断点两边的价值一样,就合并. 复杂度 \(O(n^3)\) Code /************************************************************** Problem: 4580 User: BeiYu Language: C++ Result: Ac…

Description 一个序列,每次可以将两个相同的数合成一个数,价值+1,求最后最大价值 \(n \leqslant 262144\) Sol DP. 这道题是 BZOJ 4580: [Usaco2016 Open]248 加强版. 做248的那个区间DP其实很多方案都是0,而且一个区间中只有一个合法的数字. 然后就是 一个区间合成一个数的方案的这个数字是固定的. \(f[i][j]\) 表示以 \(i\) 结尾是否能合成 \(j\),同时记录一下转移位置,每次向前找前一个指针就可以了. 复…

听说KPM初二暑假就补完了啊%%% 先刷Gold再刷Silver(因为目测没那么多时间刷Silver,方便以后TJ2333(雾 按AC数降序刷 ------------------------------------------------------------------------------------------------------- bzoj1597: [Usaco2008 Mar]土地购买  斜率优化DP h升序,w降序. f[i]=min(f[j]+h[i]*w[j+1])…

Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…

http://www.lydsy.com/JudgeOnline/problem.php?id=4580 区间dp,f(i,j)表示区间[i,j]全部合成一个数,这个数是多少. 可以归纳证明[i,j]如果可以合成一个数,那么只能合成这一个数 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N = 253; int n, a[N], f[N][N];…

4742: [Usaco2016 Dec]Team Building Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 21  Solved: 16[Submit][Status][Discuss] Description Every year, Farmer John brings his NN cows to compete for "best in show" at the state fair. His arch -rival, F…

辣鸡wyz最近状态奇差,于是想用usaco题找找手感,万万没想到被虐了一脸TAT 先贴代码,有空再填坑 4409[Usaco2016 Feb]Circular barn #include <iostream> #include <cstdio> #include <cmath> #include <cstring> #include <cstdlib> #include <algorithm> #define ll long long…

看了半天...发现就是个背包...然后就不打算敲了. 看了一眼forum..顿时吓傻..其他人用了gcd啊什么的各种奇怪的东西..然后还是敲了个背包结果就AC了= =既然写了代码就扔上来吧... ------------------------------------------------------------------------ #include<cstdio> #include<cstring> #include<algorithm>   using nam…

Android Weekly Issue #248 March 5th, 2017 Android Weekly Issue #248. 本期内容包括: 为什么有时候应该让你的应用崩溃(而不是一味保护); Trello离线模式实现中两个id的问题; 如何让Dagger的component按照scope保存, 在屏幕旋转时不重建; 用Dagger构建Realm的数据库迁移逻辑; 利用各种mock工具写单元测试; Map上markers的动画实现; JUnit5中@DisplayName的使用; R…

https://www.luogu.org/problemnew/show/P3146 一道区间dp的题,以区间长度为阶段; 但由于要处理相邻的问题,就变得有点麻烦; 最开始想了一个我知道有漏洞的方程 ][j]) f[i][j] = max(f[i][k],f[k + ][j]); ); 可能f[i][k] = f[i][j],但他们可合并的并未相邻; 可以这样 #include <bits/stdc++.h> #define read read() #define up(i,l,r) for…

传送门 Description 给定一个1*n的地图,在里面玩2048,每次可以合并相邻两个(数值范围1-40),问最大能合出多少.注意合并后的数值并非加倍而是+1,例如2与2合并后的数值为3. Input 输入的第一行是一个数字n,代表地图大小.然后n行,i+1行代表第i个数的大小 Output 输出仅一行,为最大能合并出的大小 Hint 1<=n<=248,不保证所有的数字能被合成完 Sample Input Sample Output solution 典型的区间DP.首先考虑区间dp最…

4506: [Usaco2016 Jan]Fort Moo Description Bessie is building a fort with her friend Elsie. Like any good fort, this one needs to start with a sturdy frame. Bessie wants to build a frame in the shape of a one-meter-wide rectangular outline, atop which…

4412: [Usaco2016 Feb]Circular Barn Description 有一个N个点的环,相邻两个点距离是1.点顺时针标号为1..N.每一个点有ci头牛,保证∑ci=N.每头牛都可以顺时针走.设一头牛走了d个单位停下了,将耗费d^2的能量.请设计一种牛的走法,使得每一个点上都正好有一头牛,且最小化耗费的能量. Input 第一行一个数N.N <= 100000接下来N行,每行一个数ci. Output 输出一个数表示耗费能量的最小值 Sample Input 10 1 0…

P3146 [USACO16OPEN]248 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The…

题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The game starts with a seq…

4506: [Usaco2016 Jan]Fort Moo Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 145  Solved: 104[Submit][Status][Discuss] Description Bessie正在和她的朋友Elsie建一座堡垒.像任何好的堡垒一样,这需要从一个坚固的框架开始.Bessie想要在一 个矩形上建造堡垒,并在矩形周围围上1x1的框架.Bessie已经选择了一个建造堡垒的地方 —— 一块长宽分别为 为NM…

P3146 [USACO16OPEN]248 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The…

4582: [Usaco2016 Open]Diamond Collector Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 204  Solved: 136[Submit][Status][Discuss] Description Bessie the cow, always a fan of shiny objects, has taken up a hobby of mining diamonds in her spare  time! S…

A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down). Write a function to count the total strobogrammatic numbers that exist in the range of low <= num <= high. Example: Input: low = "50"…

安装erlang的时候,使用make命令一直报这个错 Makefile:248: /usr/local/otp_src_18.1/make/x86_64-unknown-linux-gnu/otp_ded.mk: No such file or directory error: No curses library functions found 在网上找了一下解决方法. 需要安装一下 sudo yum install ncurses-devel.x86_64 然后在使用下面的命令就没有问题了 .…

P3146 [USACO16OPEN]248 题解 第一道自己码出的区间DP快庆祝一哈 2048 每次可以合并任意相邻的两个数字,得到的不是翻倍而是+1 dp[L][R] 区间 L~R 合并结果 然后拆成左区间和右区间,看看他们能不能合并,更新ans 注意如果最后枚举到的总区间 1~n ,那么就要考虑取左右区间最大值了,因为可能左右区间不能合并,那么左右区间最大值就是最终答案 代码 #include<iostream> #include<cstdio> #include<st…

[USACO16OPEN]248 G 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The gam…

[USACO16OPEN]248 G 题目: 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The…

bzoj4582[Usaco2016 Open]Diamond Collector 题意: n个钻石,每个都有一个大小,现在将其装进2个盒子里,每个盒子里的钻石最大的与最小的大小不能超过k,问最多能装多少个.n最大50000. 题解: 我真傻,真的~首先对大小排序,然后找以i为左端点的可装区间,这个操作两个指针就可以搞,我却以为要二分查找.预处理完了,因为不交错的区间肯定比交错的区间优,所以从n到1递推一下从n到i最大的区间大小是多少,然后枚举每个区间,找到当前区间大小加上右端点+1到n中最大的…

bzoj4512[Usaco2016 Jan] Build Gates 题意: 某人从农场的(0,0)出发,沿边界到处乱走,走过的地方会留下栅栏,等走完后问要在多少个栅栏上开门才能使整个农场连通,最多走1000步. 题解: 我的代码比别人的都长~我的做法是先算出最左/最下可能会走到哪里,然后变换一下坐标系(实际是是改变出发起点),然后记录哪个格子的上下左右被栅栏堵了,最后做一下floodfill,输出连通块数-1.注意还要把有栅栏区域的外圈格子也算进去,因为它们代表了有栅栏区域外的广大地区(这个…