Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 499    Accepted Submission(s): 163 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4712 解题报告:输入n个数,用十六进制的方式输入的,任意选择其中的两个数进行异或,求异或后的数用二进制表示后1的个数最小的是多少?(n<=100000) 这题看了解题报告,大家都说用随机算法,试过了,随机100000次就过了,50000次都不行,但还是不懂这样怎么可以,唯一的解释就是这个值域也就是结果一共只有21个, 得出正确的结果的可能性很大,但是并不能100%保证结果是对的.无语第一次碰见这种算…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal to the number of ones in a XOR b. For calculating Hammi…

http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 797    Accepted Submission(s): 284 Problem Description (From wikipedia) For binary…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1569    Accepted Submission(s): 616 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4712 题目大意:任意两个数按位异或后二进制中含1的个数被称为海明距离,给定n个数,求出任意其中两个最小的海明数,输入是16进制. Sample Input 2 2 12345 54321 4 12345 6789A BCDEF 0137F   Sample Output 6 7 分析:用随机数来模拟,加srand()函数,放置产生伪随机数.代码有2个. 代码1: # include<iostream…

http://acm.hdu.edu.cn/showproblem.php?pid=4712 题意:计算任意两个十六进制的数异或后1的最少个数. 思路:用随机数随机产生两个数作为下标,记录这两个数异或后1的个数,输出1的个数最少是多少. #include <stdio.h> #include <algorithm> #include <time.h> #include <math.h> using namespace std; ; <<; int…

d.汉明距离是使用在数据传输差错控制编码里面的,汉明距离是一个概念,它表示两个(相同长度)字对应位不同的数量, 我们以d(x,y)表示两个字x,y之间的汉明距离.对两个字符串进行异或运算,并统计结果为1的个数,那么这个数就是汉明距离. 给出N个串,求出其中最小的汉明距离(其中某2个串的汉明距离是最小的). s.随机数法... c.能不能过,看脸... #include<iostream> #include<stdio.h> #include<string.h> #inc…

我的做法,多次宽搜,因为后面的搜索扩展的节点会比较少,所以复杂度还是不需要太悲观的,然后加上一开始对答案的估计,用估计值来剪枝,就可以ac了. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; char a[11]; int key[111111]; int hash[1111111]; int que[2111…

http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1610    Accepted Submission(s): 630 Problem Description (From wikipedia) For bina…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1127 Accepted Submission(s): 425 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal to t…

我先解释一下汉明距离  以下来自百度百科 在信息论中,两个等长字符串之间的汉明距离是两个字符串对应位置的字符不同的个数.换句话说,它就是将 一个字符串变换成另外一个字符串所需要替换的字符个数. 例如: * 1 与 0 之间的汉明距离是 1. * 214 与 214 之间的汉明距离是 0. * "abcd" 与 "aacd" 之间的汉明距离是 1. 汉明重量是字符串相对于同样长度的零字符串的汉明距离,也就是说,它是字符串中非零的元素个数:对于二进制字符串来说,就是 1…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1845    Accepted Submission(s): 740 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equa…

第一次听说随机算法,在给的n组数据间随机取两个组比较,当随机次数达到一定量时,答案就出来了. #include<stdio.h> #include<stdlib.h> #include<string.h> #define min(a,b) (a>b?b:a) int a[101000]; int find(int b) { int ans=0; while(b) { if(b&1)ans++; b>>=1; } return ans; } in…

Hamming Distance Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 1051 Accepted Submission(s): 396 Problem Description (From wikipedia) For binary strings a and b the Hamming distance is equal to t…

link:http://acm.hdu.edu.cn/showproblem.php?pid=4712 题意:给1e5个数字,输出这些数中,最小的海明码距离. 思路:距离的范围是0到20.而且每个数的数位都很有限的,然后一言不合开始 随机.随机算法虽然挺惊艳的,不过求随机算法成功概率,臣妾做不到啊! 总之,遇上暴力很难得到优化,但AC掉一片的题,随机算法这样的奇策应当信手 拈来!这是强大洞察之力的体现~ #include <iostream> #include <algorithm>…

仔细阅读ORB的代码,发现有很多细节不是很明白,其中就有用暴力方式测试Keypoints的距离,用的是HammingLUT,上网查了才知道,hamming距离是相差位数.这样就好理解了. 我理解的HammingLUT lut; result=lut((a),(b),size_t size):result=a与b的hamming distance+size; unsigned int hamdist(unsigned int x, unsigned int y) { unsigned int di…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…

［抄题］: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Ex…

［抄题］: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanat…

[Leetcode/Javascript] 461.Hamming Distance 题目 The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note: 0 ≤ x, y < 231. Exampl…

技术背景 一般认为Jax是谷歌为了取代TensorFlow而推出的一款全新的端到端可微的框架,但是Jax同时也集成了绝大部分的numpy函数,这就使得我们可以更加简便的从numpy的计算习惯中切换到GPU的计算中.Jax除了支持GPU的张量运算,更重要的一个方面是Jax还支持谷歌自己的硬件TPU的张量运算.关于张量计算,可以参考前面写过的这一篇博客. 而标题中的另外一个概念:Hamming Distance是用来衡量两个字符串之间的相似关系评分算法,如果两个字符串的所有元素完全相同,那么就会得到…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…

题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanatio…

原题链接在这里:https://leetcode.com/problems/total-hamming-distance/ 题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs…

原题链接在这里:https://leetcode.com/problems/hamming-distance/ 题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y …

package BitManipulation; //Question 461. Hamming Distance /* The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note: 0 ≤ x,…