java 正则匹配空格字符串 正则表达式截取字符串 需求:从一堆sql中取出某些特定字符串: 比如配置的sql语句为:"company_code = @cc and project_id = @pid ; update t set a = @aa,b=@bb,c=@cd,ttt=@ttt;update t2 set d=@bb"; 我要拿出所有的以@开头的作为变量,并且去重,则如下玩: ps:其中正则匹配空格是 “\s+” public class Test { public stat…
public static void main(String[] a) { String wpp = "select 1, ${mark} '``this is, `/message22` special mark`\" this is ${mark1} special mark\"' `/message` ${mark} "; String pp = "((?=([^\\\"]*\\\"[^\\\"]*\\\")*…
1.简单匹配小案例 public static void main( String[] args ){ // 按指定模式在字符串查找 String line = "This order was placed for QT3000! OK? This is OK."; String pattern = "(OK)\\?"; // 创建 Pattern 对象 Pattern r = Pattern.compile(pattern); // 现在创建 matcher 对象…