[LeetCode] Different Ways to Add Parentheses 添加括号的不同方式

【[LeetCode] Different Ways to Add Parentheses 添加括号的不同方式】的更多相关文章

[LeetCode] Different Ways to Add Parentheses 添加括号的不同方式

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, -and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

[LeetCode] 241. Different Ways to Add Parentheses 添加括号的不同方式

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2-1)-…

【LeetCode】241. Different Ways to Add Parentheses

Different Ways to Add Parentheses Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+, - and *. Example 1 Input: "2-1-1". ((…

LN : leetcode 241 Different Ways to Add Parentheses

lc 241 Different Ways to Add Parentheses 241 Different Ways to Add Parentheses Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are…

leetcode 96. Unique Binary Search Trees 、95. Unique Binary Search Trees II 、241. Different Ways to Add Parentheses

96. Unique Binary Search Trees https://www.cnblogs.com/grandyang/p/4299608.html 3由dp[1]*dp[1].dp[0]*dp[2].dp[2]*dp[0]相加而成从2开始 class Solution { public: int numTrees(int n) { vector<); dp[] = ; dp[] = ; ;i <= n;i++){ ;j < i;j++){ dp[i] += dp[j] *…

241. Different Ways to Add Parentheses

241. Different Ways to Add Parentheses https://leetcode.com/problems/different-ways-to-add-parentheses/ 思路就是:首先找到以运算符为根节点,分别计算左子串和右子串的所有结果的集合,然后依次进行组合计算.参考博客http://www.cnblogs.com/ganganloveu/p/4681439.html. 自己的思路错了,直接用两边只用了一个整数去接收左右子串的计算值!! #include…