Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. You will have direct access to the node but not to the root of the tree.…
Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The minimum absolute difference is 1, which is the difference between 2 and 1…
4.6 Write an algorithm to find the'next'node (i.e., in-order successor) of a given node in a binary search tree. You may assume that each node has a link to its parent. 这道题实际上考察的是一种叫线索二叉树的数据结构,而构造这种树的方法称之为Morris遍历法,在我之前的博客Binary Tree Inorder Traversa…
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For exampl…
Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target. Note: Given target value is a floating point. You are guaranteed to have only one unique value in the BST that is closest to the target.…
Given a Binary Search Tree (BST) with the root node root, return the minimum difference between the values of any two different nodes in the tree. Example : Input: root = [4,2,6,1,3,null,null] Output: 1 Explanation: Note that root is a TreeNode objec…
题目230. 二叉搜索树中第K小的元素 给定一个二叉搜索树,编写一个函数 kthSmallest 来查找其中第 k 个最小的元素. 题解 中序遍历BST,得到有序序列,返回有序序列的k-1号元素. 代码 class Solution { public int kthSmallest(TreeNode root, int k) { List<Integer> list = new LinkedList<>(); inorder(root,list); return list.get(…
Leetcode:1305. 两棵二叉搜索树中的所有元素 Leetcode:1305. 两棵二叉搜索树中的所有元素 思路 BST树中序历遍有序. 利用双指针法可以在\(O(n)\)的复杂度内完成排序. 基于上述两个点,可以很简单的做出这道题. 先中序历遍得到两个有序的数列. 利用双指针法,只需历遍一次就可以得到升序的答案. Talk is cheap . Show me the code . /** * Definition for a binary tree node. * struct Tr…
Leetcode:230. 二叉搜索树中第K小的元素 Leetcode:230. 二叉搜索树中第K小的元素 思路: 利用BST的中序历遍的结果为其排序后的结果,我们可以利用其特性直接找到第k个中序遍历元素,即为问题答案. Talk is cheap . Show me the code . /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…
