1.刚开始result的初始化写的是vector<vector<int>> result,然后再去对result[0][0] = triangle[0][0]赋值,一直报错.老问题了! 2.多维vector的初始化: vector<vector<int>> result(height,vector<int>(width)) class Solution { public: int minimumTotal(vector<vector<…

vector的初始化有很多方式,在N维初始化时还会一些容易出现错误的地方.下面进行总结 以下的总结均以int作为模板参数 一维vector的初始化 vector的构造函数通常来说有五种,如下: vector():创建一个空vector vector(int nSize):创建一个vector,元素个数为nSize vector(int nSize,const t& t):创建一个vector,元素个数为nSize,且值均为t vector(const vector&):复制构造函数 vec…

题目: Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below. For example, given the following triangle [ [2], [3,4], [6,5,7], [4,1,8,3] ] The minimum path sum from top to bottom is 1…

118. Pascal's Triangle 第一种解法:比较麻烦 https://leetcode.com/problems/pascals-triangle/discuss/166279/cpp-beats-1002018.9.3(with-annotation) class Solution { public: vector<vector<int>> generate(int numRows) { vector<vector<int>> result;…

题目详情 给定一个三角形,找出自顶向下的最小路径和.每一步只能移动到下一行中相邻的结点上. 例如,给定三角形: [ [2], [3,4], [6,5,7], [4,1,8,3] ] 自顶向下的最小路径和为 11(即,2 + 3 + 5 + 1 = 11). 说明: 如果你可以只使用 O(n) 的额外空间(n 为三角形的总行数)来解决这个问题,那么你的算法会很加分. 解决代码(1)-- 空间复杂度为O(N^2) 解决思路 这个题目非常明显的动态规划问题, 当前节点的最小值由前面一层的一个(当为第一…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous ro…

11.6 Given an M x N matrix in which each row and each column is sorted in ascending order, write a method to find an element. LeetCode上的原题,请参见我之前的博客Search a 2D Matrix 搜索一个二维矩阵和Search a 2D Matrix II 搜索一个二维矩阵之二. class Solution { public: bool findElemen…

二维vectorvector<vector <int> > ivec(m ,vector<int>(n));    //m*n的二维vector 动态创建m*n的二维vector方法一:vector<vector <int> > ivec;ivec.resize(m);for(int i=0;i<m;i++) ivec[i].resize(n); 方法二:vector<vector <int> > ivec;ivec…

最近调试一个程序,在使用vector声明一个二维数组时出现错误.错误的方法如下所示: std::vector<std::vector<double> > sphereGrid; int gridLA = angleSpanLA / angelAccuracy; int gridLO = angleSpanLO / angelAccuracy; sphereGrid = std::vector<std::vector<double> >( gridLA , g…