Portal Description 给出一个\(n(n\leq35000)\)个数的数列\(\{a_i\}\)和\(m(m\leq50)\).将原数列划分成\(m\)个连续的部分,每个部分的权值等于其中不同的数的个数.求所有划分方案中,所有部分权值和中的最大值. Solution 线段树优化DP. 记录\(f[k][i]\)表示将前\(i\)个数划分为\(k\)段的最大权值和,\(w(i,j)\)表示\([L,R]\)的权值,那么容易列出转移方程: \[ f[k][i]=max\{f[k-1]…

B. Bakery time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads,…

Bakery 题目链接: http://codeforces.com/contest/707/problem/B Description Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads, each of whose connects some pair of cities. To bake…

面包店烹制面包及蛋糕,由n个销售员卖出.当有顾客进店购买面包或蛋糕时,应先在取号机上取号,然后等待叫号,若有销售员空闲时便叫下一号,试用信号量和PV操作写出Bakery算法的同步程序. 设计要求 1)为每个销售员/顾客产生一个进程/线程,设计正确的同步算法: 2)每个顾客进入面包店后,即时显示"Entered",还同时显示共有几名顾客: 3)至少有个顾客: 4)多个销售员/顾客程序须共享操作函数代码. 专业程序代写c++程序代写…

D. The Bakery time limit per test:2.5 seconds memory limit per test:256 megabytes input:standard input output:standard output Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven whic…

Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which can bake several types of cakes, and opened the bakery. Soon the expenses started to overcome the income, so Slastyona decid…

B. The Bakery time limit per test 2.5 seconds memory limit per test 256 megabytes input standard input output standard output Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven whic…

B. Bakery 题目连接: http://www.codeforces.com/contest/707/problem/B Description Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads, each of whose connects some pair of cities.…

834D - The Bakery 思路:dp[i][j]表示到第j个数为止分成i段的最大总和值. dp[i][j]=max{dp[i-1][x]+c(x+1,j)(i-1≤x≤j-1)},c(x+1,j)表示x+1到j的不同的值. 用线段树维护一下最大值. 上图最后一个点取不到,不解释,不明白请评论. 代码: #include<bits/stdc++.h> using namespace std; #define ll long long #define ls rt<<1,l,m…

CF833B The Bakery LG传送门 线段树优化DP. 其实这是很久以前就应该做了的一道题,由于颓废一直咕在那里,其实还是挺不错的一道题. 先考虑\(O(n^2k)\)做法:设\(f[i][j]\)表示\(1\)到\(i\)之间分割\(j\)次得到的最大值,\(g[i][j]\)表示\(i\)到\(j\)之间不同的颜色个数. 转移就是: \[f[i][j]=max \{f[t][j-1]+g[t+1][i] \} \qquad t \in [1,i)\] 但是时空都无法承受,考虑优化.…

Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads, each of whose connects some pair of cities. To bake muffins in her bakery, Masha needs to establish flour supply from so…

B. The Bakery http://codeforces.com/contest/833/problem/B 题意: 将一个长度为n的序列分成k份,每份的cost为不同的数的个数,求最大cost的和.1≤n≤35000,1≤k≤50 分析: dp[i][j]表示前i个数,分了j份.dp[i][k]=dp[j][k-1]+cost(j+1,i):cost(j+1,i)为这一段中不同数的个数. 然后考虑如何优化.发现每次增加一个位置,pre[i]~i-1区间的每个转移的位置的cost+1.然后…

B. The Bakery time limit per test 2.5 seconds memory limit per test 256 megabytes input standard input output standard output Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven whic…

Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads, each of whose connects some pair of cities. To bake muffins in her bakery, Masha needs to establish flour supply from so…

Codeforces 834D The Bakery LINK 题目大意是给你一个长度为n的序列分成k段,每一段的贡献是这一段中不同的数的个数,求最大贡献 是第一次做线段树维护DP值的题 感觉还可以,虽然看了一下这题是用线段树维护DP值 然后说思路 有一个很显然的思路是这样的: dpi,j表示前i个数分成j段的最大贡献 dpi,j=max(dpk,j−1+calc(k+1,i)) 然后我们就可以对于每一层j用线段树维护起来 然后就非常愉快地发现dp[i][p]只会从dp[i−1][p−1]之前的…

Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which can bake several types of cakes, and opened the bakery. Soon the expenses started to overcome the income, so Slastyona decid…

 The Bakery time limit per test 2.5 seconds memory limit per test 256 megabytes input standard input output standard output Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which…

Description Masha wants to open her own bakery and bake muffins in one of the n cities numbered from 1 to n. There are m bidirectional roads, each of whose connects some pair of cities. To bake muffins in her bakery, Masha needs to establish flour su…

codeforces 834 D. The Bakery(dp + 线段树优化) 题意: 给一个长度为n的序列分成k段,每段的值为这一段不同数字的个数,最大化划分k端的值 $n <= 35000 $ \(k <= min(n,50)\) 思路: 由于k比较小,直接dp就好了 \(dp[i][j]\)选了k段到j的最大值 \(dp[i][j] = max(dp[i-1][k]+diff(k+1,j)) (0 <= k < j)\) 然后用线段树优化一下, 一个数的贡献是上一个相同数字…

题目链接: B. Bakery 题意: 是否存在一条连接特殊和不特殊的边,存在最小值是多少; 思路: 扫一遍所有边: AC代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include &l…

D. The Bakery time limit per test 2.5 seconds memory limit per test 256 megabytes input standard input output standard output Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven whic…

题目链接 The Bakery 题目大意:目标是把$n$个数分成$k$组,每个组的值为这个组内不同的数的个数,求$k$个组的值的和的最大值. 题目分析: 这道题我的解法可能和大众解法不太一样……我用主席树求$ask(l, r)$——$l$到$r$之间有多少个不同的数. 然后就是$DP$了. 这道题的数据规模是 $n <= 35000$, $k <= 50$ 首先直接$DP$的做法还是比较简单的.代码如下. 其中$f[i][j]$为前$i$个数分成$j$组可以得到的最大的和 rep(i, 1,…

D. The Bakery   Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which can bake several types of cakes, and opened the bakery. Soon the expenses started to overcome the income, so…

Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which can bake several types of cakes, and opened the bakery. Soon the expenses started to overcome the income, so Slastyona decid…

  Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which can bake several types of cakes, and opened the bakery. Soon the expenses started to overcome the income, so Slastyona dec…

The Bakery 题意:将N个数分成K块, 每块的价值为不同数字的个数, 现在求总价值最大. 题解:dp[i][j] 表示 长度为j 且分成 i 块的价值总和. 那么 dp[i][j] = max(dp[i-1][x]+右边的数的贡献) ( 1<=x < j ). 如果每次都从左到右for过去一定会TLE, 所以我们用线段树来优化这个查询的过程, 并且用滚动数组消去第二维空间. 每次新扫到一个数T, 他就会在上一个T的位置+1 --- 现在这个T的位置产生数目加一的贡献. 然后每次扫完一次…

Bakery Descriptions 玛莎想在从1到n的n个城市中开一家自己的面包店,在其中一个城市烘焙松饼. 为了在她的面包房烘焙松饼,玛莎需要从一些储存的地方建立面粉供应.只有k个仓库,位于不同的城市编号为a1, a2,…,ak. 不幸的是,玛莎居住的那个国家的法律禁止在任何一个有仓库的城市开设面包店.她只能在另一个n - k城市中的一个开这家店,当然,面粉配送也要付费——从仓库到面包房每走一公里,玛莎就得支付1卢布. 形式上,玛莎将支付x卢布,如果她将打开面包店在一些城市b (ai≠b每…

B. The Bakery time limit per test 2.5 seconds memory limit per test 256 megabytes input standard input output standard output Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven whic…

D - The Bakery CodeForces - 834D 这个题目好难啊,我理解了好久,都没有怎么理解好, 这种线段树优化dp,感觉还是很难的. 直接说思路吧,说不清楚就看代码吧. 这个题目转移方程还是很好写的, dp[i][j]表示前面 i 个蛋糕 分成了 j 个数字的最大价值. dp[i][j]=max(dp[k][j-1]+val[k+1~i]) 显而易见的是,这个肯定不可以直接暴力求,所以就要用到线段树优化. 线段树怎么优化呢, 先看这个问题,给你一个点 x ,问你以这个点为右端…

B. The Bakery   Some time ago Slastyona the Sweetmaid decided to open her own bakery! She bought required ingredients and a wonder-oven which can bake several types of cakes, and opened the bakery. Soon the expenses started to overcome the income, so…