Another Meaning Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 917    Accepted Submission(s): 434 Problem Description As is known to all, in many cases, a word has two meanings. Such as “hehe”,…

Another Meaning 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5763 Description As is known to all, in many cases, a word has two meanings. Such as "hehe", which not only means "hehe", but also means "excuse me". Today, ?? i…

HDU 5763 Another Meaning 题意:一个字串有可能在模式串出现多次,问有多少种可能出现的情况.关键是有重合的字串是不能同时计入的. 思路:先用kmp求出所有字串的位置.然后,dp. 二维的时候:dp[i][j] i表示前i个子串,j的值1表示一定用这个串,0表示不用.值表示字串出现的情况数. 一维的时候可以直接用dp[i] 表示前i个字串能出现的情况. 然后,状态转移就都是分为三种情况: 1)当前子串和前一个子串不冲突,dp[i] = dp[i-1] * 2. 或者 dp[i…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5763 Another Meaning Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/65536 K (Java/Others) 问题描述 As is known to all, in many cases, a word has two meanings. Such as "hehe", which not only…

题目大意:给你两个串,一长一短,如果长串中某个子串和短串完全相同,则这个子串可以被替换成"#",求长串所有的表达形式....... 比如"hehehehe"和"hehe",则有5种情况,"#hehe","he#he","hehe#","##","hehehehe" 首先我们KMP/哈希找出长串中所有可以作为和短串结尾匹配成功后的位置 然后可以得到方…

http://acm.hdu.edu.cn/showproblem.php?pid=5763 题意: 给出一个字符串和一个模式串,模式串有两种意思,问这句话有几种意思. 思路:因为肯定要去字符串去找模式串,所以首先用KMP计算next数组,然后用动态规划,d[i]表示分析到第i个字符时有多少种意思. #include<iostream> #include<algorithm> #include<cstring> #include<cstdio> #inclu…

题意:给定一个句子str,和一个单词sub,这个单词sub可以翻译成两种不同的意思,问这个句子一共能翻译成多少种不能的意思 例如:str:hehehe   sub:hehe 那么,有**he.he**.和hehehe三种不同的意思, 考虑一下aaadaaa这种情况?sub:aa  前面的aaa有三种,后面的aaa有三种,所以一共应该是有9种情况. 可以考虑成3*3=9 如果你考虑分块去相乘的话,那么恭喜你,你GG了.因为这样写非常复杂,而且非常难判断. 可以考虑下dp,因为注意到,它每个单词只有…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5763 题目大意: T组数据,给两个字符串s1,s2(len<=100000),s2可以被解读成2种意思,问s1可以解读成几种意思(mod 1000000007). 题目思路: [动态规划][KMP] 题目有点绕,看看样例就懂了.其实不用KMP直接用substr就能做. 首先不解读成另一个意思的话,f[i]=f[i-1],接着如果当前位置能够与s2匹配,那么f[i]+=f[i-strlen(s2)]…

[题目链接] http://acm.hdu.edu.cn/showproblem.php?pid=5763 [题目大意] 给出两个串S和T,可以将S串中出现的T替换为*,问S串有几种表达方式. [题解] 我们定义数组f为S串中T出现的最后一个字母所在的位置,那么ans[i]=ans[i-1]+f[i-1]?ans[i-lenT]:0,一遍递推即可,所以关键就在于求出f数组了,f数组可以用kmp求,由于最近练FFT,用FFT求距离卷积匹配为0的位置,就是f数组了. [代码] #include <c…

http://acm.hdu.edu.cn/showproblem.php?pid=5763 Another Meaning Problem Description   As is known to all, in many cases, a word has two meanings. Such as “hehe”, which not only means “hehe”, but also means “excuse me”. Today, ?? is chating with MeiZi…