307. Range Sum Query - Mutable 思路:利用线段树,注意数据结构的设计以及建树过程利用线段树,注意数据结构的设计以及建树过程 public class NumArray { class segmentNode{ int start; int end; segmentNode left; segmentNode right; int sum; public segmentNode(int start,int end){ this.start = start; this.…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

原文链接:线段树(Segment Tree) 1.概述 线段树,也叫区间树,是一个完全二叉树,它在各个节点保存一条线段(即“子数组”),因而常用于解决数列维护问题,基本能保证每个操作的复杂度为O(lgN). 线段树是一种二叉搜索树,与区间树相似,它将一个区间划分成一些单元区间,每个单元区间对应线段树中的一个叶结点. 对于线段树中的每一个非叶子节点[a,b],它的左儿子表示的区间为[a,(a+b)/2],右儿子表示的区间为[(a+b)/2+1,b].因此线段树是平衡二叉树,最后的子节点数目为N,即…

A template of discretization + scaning line + segment tree. It's easy to understand, but a little difficult for coding as it has a few details. #include"Head.cpp" const int N=207; double x[N<<1]; struct Point{ double l,r,h; int w; bool ope…

// 我的代码 package Leetcode; /** * 199. Binary Tree Right Side View * address: https://leetcode.com/problems/binary-tree-right-side-view/ * Given a binary tree, imagine yourself standing on the right side of it, * return the values of the nodes you can…

Revenge of Segment Tree Problem Description In computer science, a segment tree is a tree data structure for storing intervals, or segments. It allows querying which of the stored segments contain a given point. It is, in principle, a static structur…

The structure of Segment Tree is a binary tree which each node has two attributes startand end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end is given bybuild method…

The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end is given by build meth…

判断一棵树是否自对称 可以回忆我们做过的Leetcode 100 Same Tree 二叉树和Leetcode 226 Invert Binary Tree 二叉树 先可以将左子树进行Invert Binary Tree,然后用Same Tree比较左右子树 而我的做法是改下Same Tree的函数,改动的是第27行 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left;…

LeetCode:Construct Binary Tree from Inorder and Postorder Traversal Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree.                                            …

For a Maximum Segment Tree, which each node has an extra value max to store the maximum value in this node's interval. Implement a modify function with three parameterroot, index and value to change the node's value with[start, end] = [index, index] …

Segment Tree Query I For an integer array (index from 0 to n-1, where n is the size of this array), in the corresponding SegmentTree, each node stores an extra attribute max to denote the maximum number in the interval of the array (index from start…

Segment Tree Build I The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end i…

For an array, we can build a SegmentTree for it, each node stores an extra attribute count to denote the number of elements in the the array which value is between interval start and end. (The array may not fully filled by elements) Design a query me…

For a Maximum Segment Tree, which each node has an extra value max to store the maximum value in this node's interval. Implement a modify function with three parameter root, index and value to change the node's value with [start, end] = [index, index…

For an integer array (index from 0 to n-1, where n is the size of this array), in the corresponding SegmentTree, each node stores an extra attribute max to denote the maximum number in the interval of the array (index from start to end). Design a que…

The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end is given by build meth…

Revenge of Segment Tree Problem DescriptionIn computer science, a segment tree is a tree data structure for storing intervals, or segments. It allows querying which of the stored segments contain a given point. It is, in principle, a static structure…

Do use segment tree Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://www.bnuoj.com/v3/problem_show.php?pid=39566 Description Given a tree with n (1 ≤ n ≤ 200,000) nodes and a list of q (1 ≤ q ≤ 100,000) queries, process the queries in order and out…

http://www.spoj.com/problems/SEGSQRSS/ SPOJ Problem Set (classical) 11840. Sum of Squares with Segment Tree Problem code: SEGSQRSS Segment trees are extremely useful.  In particular "Lazy Propagation" (i.e. see here, for example) allows one to c…

HDURevenge of Segment Tree(第二长的递增子序列) 题目链接 题目大意:这题是求第二长的递增子序列. 解题思路:用n^2的算法来求LIS,可是这里还要记录一下最长的那个序列是否有多种组成方式,假设>= 2, 那么第二长的还是最长的LIS的长度,否则就是LIS - 1: 代码: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; cons…

Revenge of Segment Tree Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 383    Accepted Submission(s): 163 Problem Description In computer science, a segment tree is a tree data structure for s…

HDU5086Revenge of Segment Tree(数论) pid=5086" target="_blank" style="">题目链接 题目大意:给出长度为n的数组.然后要求累计里面的每一个子串的和. 解题思路:枚举起点和终点,推断每一个数属于多少条线段.那么这个数就要被加这么多次.能够得出每一个位置被加次数的公式: i (n - i + 1):那么结果就是累计(arr[i] i) mod * (n - i + 1) % mod,注意两…

[题目描述] For an array, we can build a Segment Tree for it, each node stores an extra attribute count to denote the number of elements in the the array which value is between interval start and end. (The array may not fully filled by elements) Design a…

更新了基础部分 更新了\(lazytag\)标记的讲解 线段树 Segment Tree 今天来讲一下经典的线段树. 线段树是一种二叉搜索树,与区间树相似,它将一个区间划分成一些单元区间,每个单元区间对应线段树中的一个叶结点. 简单的说,线段树是一种基于分治思想的数据结构,用来维护序列的区间特殊值,相对于树状数组,线段树可以做到更加通用,解决更多的区间问题. 性质 1.线段树的每一个节点都代表了一个区间 2.线段树是一棵二叉树,具有唯一的根节点,其中,根节点代表的是整个区间\([1,n]\) 3…

Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 Output: [3,2,1] Follow up: Recursive solution is trivial, could you do it iteratively? --------------------------------------------------…

leetcode 199. Binary Tree Right Side View 这个题实际上就是把每一行最右侧的树打印出来,所以实际上还是一个层次遍历. 依旧利用之前层次遍历的代码,每次大的循环存储的是一行的节点,最后一个节点就是想要的那个节点 class Solution { public: vector<int> rightSideView(TreeNode* root) { vector<int> result; if(root == NULL) return resul…

Segment Tree Beats 区间最值问题 线段树一类特殊技巧! 引出:CF671C Ultimate Weirdness of an Array 其实是考试题,改题的时候并不会区间取最值,区间求和,之后秉承着好好学习的态度,学习了Segment tree Beats 套路是维护出区间最小值和次小值,以及区间最小值数量.之后再维护出题目中需要的东西就好了.之后怎么处理呢,如果我们需要维护出区间和x取max,那么,如果x<=minn[rt],那么直接return;如果x<minx[rt]…

题目链接 区间取\(\max,\ \min\)并维护区间和是普通线段树无法处理的. 对于操作二,维护区间最小值\(mn\).最小值个数\(t\).严格次小值\(se\). 当\(mn\geq x\)时,不需要改变,return:\(se>x>mn\)时,\(sum=sum+(x-mn)*t\),打上区间\(\max\)标记: 当\(x\geq se>mn\)时,不会做,继续递归分别处理两个子区间,直到遇到前两种情况. 操作三同理,维护最大值.最大值个数.次大值. 复杂度\(O(m\log…

Revenge of Segment Tree                                                          Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)                                                                                    To…