870. Advantage Shuffle

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贪心:leetcode 870. Advantage Shuffle、134. Gas Station、452. Minimum Number of Arrows to Burst Balloons、316. Remove Duplicate Letters

870. Advantage Shuffle 思路:A数组的最大值大于B的最大值,就拿这个A跟B比较:如果不大于,就拿最小值跟B比较 A可以改变顺序,但B的顺序不能改变,只能通过容器来获得由大到小的顺序,并且必须存储相应的index,因为最终需要将选择的A的数值存入与这个B相对应的index下 class Solution { public: vector<int> advantageCount(vector<int>& A, vector<int>&…

【LeetCode】870. Advantage Shuffle 解题报告（Python）

[LeetCode]870. Advantage Shuffle 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/advantage-shuffle/description/ 题目描述: Given two arrays A and B of equal size, the advantage of A with respect to B…

Given two arrays A and B of equal size, the advantage of A with respect to B is the number of indices i for which A[i] > B[i]. Return any permutation of A that maximizes its advantage with respect to B. Example 1: Input: A = [2,7,11,15], B = [1,10,4,…

【leetcode】870. Advantage Shuffle

题目如下: 解题思路:几千年前,一个古人曾经解过这个题目,他的名字叫做田忌,后人称他的解题思想叫做“田忌赛马”.言归正传,本题就是一个田忌赛马的问题,先将A与B进行排序,然后判断A[0]与B[0]的大小,如果A[0] > B[0],那么A[0]和B[0]就是一对,将A[0]和B[0]同时从数组删除:如果A[0] <= B[0],把A[0]存入一个holdspace,同时删除A[0],一直循环,直到len(A) = 0 为止,这些都是Advantage.如果B还有元素的话,那么就用holdspa…

[LeetCode] Advantage Shuffle 优势洗牌

Given two arrays A and B of equal size, the advantage of A with respect to B is the number of indices i for which A[i] > B[i]. Return any permutation of A that maximizes its advantage with respect to B. Example 1: Input: A = [2,7,11,15], B = [1,10,4,…

[Swift]LeetCode870. 优势洗牌 | Advantage Shuffle

Given two arrays A and B of equal size, the advantage of A with respect to B is the number of indices i for which A[i] > B[i]. Return any permutation of A that maximizes its advantage with respect to B. Example 1: Input: A = [2,7,11,15], B = [1,10,4,…