头文件:#include <math.h> atan2() 函数用于求 y / x 的反正切值.其原型为: double atan2(double y, double x); [参数]x为坐标的X轴值,y为坐标的Y轴值.如果 x 和 y 的值都为 0,将会导致错误. atan2() 求坐标 x 和 y 的坐标的反正切值.反正切的角度值等于 X 轴与通过原点和给定坐标点的直线之间的夹角.结果以弧度表示,并介于 -π 到 π 之间. 在三角函数中,两个参数的函数 atan2() 是正切函数的…
//输入一组整数.求出这组数字子序列和中最大值 #include <stdio.h> int MAxSum(int arr[],int len) { int maxsum = 0; int i; int j; for (i = 0; i < len; i++) { int thissum = 0; for (j = i; j < len; j++) { thissum += arr[j]; if (thissum>maxsum) maxsum = thissum; } } r…
原文:http://www.zhufengpeixun.cn/JavaScriptmianshiti/2014-04-01/287.html < script type = "text/javascript" > var x = 1; var y = 0; var z = 0; function add(n) { n = n + 1; } y = add(x); function add(n) { n = n + 3; } z = add(x); s = y + z; &l…
题目链接 495. Kids and Prizes Time limit per test: 0.25 second(s)Memory limit: 262144 kilobytes input: standardoutput: standard ICPC (International Cardboard Producing Company) is in the business of producing cardboard boxes. Recently the company organiz…
Super Jumping! Jumping! Jumping! Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1087 Appoint description: System Crawler (2017-04-13) Description Nowadays, a kind of chess game called “Super…