HDOJ(HDU).3466 Dividing coins ( DP 01背包 无后效性的理解) 题意分析 要先排序,在做01背包,否则不满足无后效性,为什么呢? 等我理解了再补上. 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 505 #define nn 505*100 using namespace std;…

HDOJ(HDU).2546 饭卡(DP 01背包) 题意分析 首先要对钱数小于5的时候特别处理,直接输出0.若钱数大于5,所有菜按价格排序,背包容量为钱数-5,对除去价格最贵的所有菜做01背包.因为这时候还剩下5块钱,直接买最贵的那个菜,就可以保证剩下来的钱数是最小的. 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nma…

HDOJ(HDU).2602 Bone Collector (DP 01背包) 题意分析 01背包的裸题 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 1005 using namespace std; int v[nmax],w[nmax],dp[nmax]; int main() { //freopen("in…

Dividing coins It's commonly known that the Dutch have invented copper-wire. Two Dutch men were fighting over a nickel, which was made of copper. They were both so eager to get it and the fighting was so fierce, they stretched the coin to great lengt…

  Dividing coins  It's commonly known that the Dutch have invented copper-wire. Two Dutch men were fighting over a nickel, which was made of copper. They were both so eager to get it and the fighting was so fierce, they stretched the coin to great le…

http://acm.hdu.edu.cn/showproblem.php?pid=1561 很容易想到如果是要攻克v城需要先攻克u城的话,可以建u到v的边.但是如果能够直接攻克u城呢?无边可建,这样就无法形成一棵树.因此虚拟出一个0结点去连接可直接攻克的城.这样只需多打一次0城即可.定义状态dp[i][j]表示当前结点为i时,选取j个节点(j为i的子节点或i)能获得的最大价值. dp[u][j]=max(dp[u][j],dp[u][j-k]+dp[v[u][i]][k])表示:在u号点的第i…

题意:给你n个硬币,和n个硬币的面值.要求尽可能地平均分配成A,B两份,使得A,B之间的差最小,输出其绝对值.思路:将n个硬币的总价值累加得到sum,   A,B其中必有一人获得的钱小于等于sum/2,另一人获得的钱大于等于sum/2.   因此用sum/2作为背包容量对n个硬币做01背包处理,   所能得到的最大容量即为其中一人获得的钱数. #include <iostream> #include <cstdio> #include <cstring> #includ…

http://acm.hdu.edu.cn/showproblem.php?pid=3466 题意: 最近,iSea去了一个古老的国家.在这么长的时间里,它是世界上最富有和最强大的王国.结果,这个国家的人民仍然非常自豪,即使他们的国家没有那么富有了.商人是最典型的,每个人只卖一个项目,价格是Pi,但如果你的钱少于Qi,他们会拒绝与你交易,iSea评估每个项目一个值Vi.如果他有M单位的钱,iSea可以获得的最大价值是多少? 思路: 这道题的话多加了一个Qi. 一定要注意,若要保证动归方程无后效性…

It's commonly known that the Dutch have invented copper-wire. Two Dutch men were fighting over a nickel, which was made of copper. They were both so eager to get it and the fighting was so fierce, they stretched the coin to great length and thus crea…

这道题目看出背包非常easy.主要是处理背包的时候须要依照q-p排序然后进行背包. 这样保证了尽量多的利用空间. Proud Merchants Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others) Total Submission(s): 2674    Accepted Submission(s): 1109 Problem Description Recently, iSea…