题意:数字反转 思路:醉了,提交了好几次,难点不在于怎么反转,而是判断是否益处,原题中给的是int,4个字节,32位,开始不知道怎么判断.现在知道了是limits.h中的INT_MIN和INT_MAX作为int的下界和上界. 代码: ; ) { s = s * + x % ; x = x / ; } : s; 顺便附上对各个数据类型范围介绍: 类型名称                  字节数            取值范围signed char               1        …

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throug…

问题描述 Example1: x = 123, return 321 Example2: x = -123, return -321 原题链接: https://leetcode.com/problems/reverse-integer/ 解决方案 public int reverse(int x) { long res = 0; //need to consider the overflow problem while(x != 0){ res = res * 10 + x % 10; //…

题目描述: 解题思路: 反转的方法很简单,重点在于判断溢出的问题,下面给出了两种方法. Java代码: 方法一: 判断溢出方法:在执行完int newResult=result*10+tail语句后,紧接着进行逆运算result=(newResult-tail)/10,如果出现溢出,那么逆运算后result和newResult必然不相等,反之,如果没有溢出,则逆运算后result=newResult. public class LeetCode7 { public static void mai…

Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only store integers within…

Problem: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem…

Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the integer'…

Integer.parseInt 处理一个空字符串, 结果出错了, 程序没有注意到,搞了很久, 引发了血案啊!! 最后,终于 观察到了, 最后的部分: Caused by: java.lang.NoClassDefFoundError: Could not initialize class com.lk.common.util.LKUtil 还以为是class 不存在呢!! 于是,反复的复制啊, 黏贴啊, 我擦, 明明LKUtil就在那里的啊!!! 怎么回事! 实际原因就是这个啊: Caused…

最近看到一个多线程面试题,有三个线程分别打印A.B.C,请用多线程编程实现,在屏幕上循环打印10次ABCABC- 看到这个题目,首先想到的是解决方法是定义一个Integer类对象,初始化为0,由3个线程共享,如果Integer对象取余3之后等于0,则打印A,同时进行加1操作:如果Integer对象取3之后等于1,则打印B,同时进行加1操作:如果Integer对象取3之后等于1,则打印C,如果循环打印了10次的话,就退出线程. /** * ThreeThread * 3个线程测试 */ publi…

Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Input: 8 Outp…