Given an array A, partition it into two (contiguous) subarrays left and right so that: Every element in left is less than or equal to every element in right. left and right are non-empty. left has the smallest possible size. Return the length of left…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/partition-array-into-disjoint-intervals/description/ 题目描述: Given an array A, partition it into two (contiguous) subarrays left and right so that: Every elemen…

题目如下: 解题思路:题目要求的是在数组中找到一个下标最小的index,使得index左边(包括自己)子序列的最大值小于或者等于右边序列的最小值.那么我们可以先把数组从最左边开始到数组最右边所有子序列的最大值都求出来存入leftMax数组,同时也把从数组最右边开始到最左边的所有子序列的最小值求出来存入rightMin数组,最后找出最小的i使得leftMax[i] <= rightMin[i+1]即可. 代码如下: class Solution(object): def partitionDisj…

Given an array A, partition it into two (contiguous) subarrays left and right so that: Every element in left is less than or equal to every element in right. left and right are non-empty. left has the smallest possible size. Return the length of left…

Given an array A, partition it into two (contiguous) subarrays left and right so that: Every element in left is less than or equal to every element in right. left and right are non-empty. left has the smallest possible size. Return the length of left…

2020-02-10 22:16:50 问题描述: 问题求解: 解法一:MultiSet O(nlog) 看了下数据规模,第一个想到的是multiset,肯定可以ac的,就直接敲了出来. public int partitionDisjoint(int[] A) { TreeMap<Integer, Integer> map = new TreeMap<>(); for (int num : A) map.put(num, map.getOrDefault(num, 0) + 1)…

https://leetcode.com/problems/data-stream-as-disjoint-intervals/ Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the da…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given an array A, partition it into two (contiguous) subarrays left and right so that: Every element in left is less than or equal to every element in right. left and right are non-empty. left has the smallest possible size. Return the length of left…

原题链接在这里:https://leetcode.com/problems/partition-array-for-maximum-sum/ 题目: Given an integer array A, you partition the array into (contiguous) subarrays of length at most K.  After partitioning, each subarray has their values changed to become the ma…