Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 思路:两个递归…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 22: Generate Parentheseshttps://oj.leetcode.com/problems/generate-parentheses/ Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.For exa…

一.题目说明 这个题目是22. Generate Parentheses,简单来说,输入一个数字n,输出n对匹配的小括号. 简单考虑了一下,n=0,输出"";n=1,输出"()":n=2,输出"()()","(())"... 二.我的解法 我考虑了一下,基本上2种思路,其1是暴力破解法,就是列出所有可能情况,然后判断哪些是匹配的. 汗颜的是,我没做出来.找到的答案: #include<iostream> #incl…

22. Generate Parentheses . Generate Parentheses Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = , a solution set is: [ "((()))", "(()())", "(())()"…

Generate Parentheses Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] AC…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]   …

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] pub…

题目描述: Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 解…

https://leetcode.com/problems/generate-parentheses/ Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()&q…

一天一道LeetCode (一)题目 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "(…

［抄题］: Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()"…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 题意:…

题目 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]…

题目 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 思路:…

题目描述: Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. 解题分析: 这类题一般都要用递归的方法来解决.需要设两个集合类分别存储待匹配的(,)的个数. 这里需要明白一点:当待匹配的(的个数永远不小于待匹配的)的个数时只能匹配(,否则会导致错误.(可以自己在纸上试一下就好理解了),其余情况可以考虑匹配( 和)两种情况下可能的结果. 具体代…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 解法:…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 根据题…

题目 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n=3, a solution set is:  [   "( ( ( ) ) )",   "( ( ) ( ) )",   "( ( ) ) ( )",   "( ) ( ( ) )&q…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:括号, 括号生成,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 回溯法 日期 题目地址:https://leetcode.com/problems/generate-parentheses/description/ 题目描述 Given n pairs of parentheses, write…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] cla…

I thought I know Python... Actually , I know nothing... 这个题真想让人背下来啊,每一句都很帅!!! Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" /** * R…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] Tim…

https://leetcode.com/problems/generate-parentheses/ 题目大意:给出n对小括号,求出括号匹配的情况,用列表存储并返回,例如:n=3时,答案应为: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]解题思路:想到递归的思想,判断匹配成功(递归返回)的条件为:左右括号数保持一致并且括号字符串的长度等于2*n.…

把左右括号剩余的次数记录下来,传入回溯函数. 判断是否得到结果的条件就是剩余括号数是否都为零. 注意判断左括号是否剩余时,加上left>0的判断条件!否则会memory limited error! 判断右括号时要加上i==1的条件,否则会出现重复的答案. 同样要注意在回溯回来后ans.pop_back() class Solution { public: void backTrack(string ans, int left, int right, vector<string>&…

题目链接 : https://leetcode.com/problems/generate-parentheses/?tab=Description   给一个整数n,找到所有合法的 () pairs    For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 递归程…

题目大意:给n个'(' 和 ')',构造出所有的长度为2*n并且有效的(可匹配的)字符串. 题目分析:这道题不难,可以直接搜索出所有可能的字符串,然后再逐一判断是否合法即可.但是还有更好的办法,实际上,“判断是否合法”这一操作是冗余的,如果可以直接朝着满足可匹配性的方向进行构造,就可避免这一冗余操作,这需要换一个角度思考. 一个有效(可匹配)字符串中, '(' 的个数决定了 ')' 的个数(从左向右看).所以,初始时,可以看成是 “有n个 '('  还没有用.有0个 ')'  必须要用”.这样,…

思路: 递归解决,如果左括号个数小于右括号或者左括号数小于总括号对数,则生成一个左括号,如果左括号数大于右括号,生成一个右括号. class Solution { public: vector<string> ans; int num; void brackets(string res, int left, int right, int sum) { * num) { ans.push_back(res); } else{ , right, sum + ); , sum + ); } } ve…