Sum Time Limit: 2000/1000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others) SubmitStatisticNext Problem Problem Description You are given an N*N digit matrix and you can get several horizontal or vertical digit strings from any position. For…

聚合函数:sum,count,max,avg等,一般作用于多条记录上.通过group by可以将数据对属于一组的数据起作用. SELECT region, SUM(population), SUM(area)FROM bbc GROUP BY region having子句,汇总之后再筛选.作用于组,从而选择满足条件的组.比如说下面这个,就不能使用where,因为已经分组了,就不能再对一条记录进行操作了. SELECT region, SUM(population), SUM(area) FRO…

题目: Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. For example, 1 / \…

时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:2109 解决:901 题目描述: John von Neumann, b. Dec. 28, 1903, d. Feb. 8, 1957, was a Hungarian-American mathematician who made important contributions to the foundations of mathematics, logic, quantum physics, meteorology, scienc…

Divide Sum Time Limit: 2000/1000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others) SubmitStatisticNext Problem Problem Description long long ans = 0;for(int i = 1; i <= n; i ++)    for(int j = 1; j <= n; j ++)        ans += a[i] / a[j];给出n,a…

Sum vs Product Time Limit: 4000/2000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others) SubmitStatisticNext Problem Problem Description Peter has just learned mathematics. He learned how to add, and how to multiply. The fact that 2 + 2 = 2 × 2…

转自:http://lxw1234.com/archives/2015/04/176.htm,Hive分析窗口函数(一) SUM,AVG,MIN,MAX 之前看到大数据田地有关于max()over(partition by)的用法,今天恰好工作中用到了它,但是使用中遇到了一个问题:在max(rsrp)over(partition by buildingid,height) as max_rsrp返回的结果不是分组中的最大值.最中找到了问题的原因:max_rsrp数据类型为string而不是dou…

题目链接 题目要求: Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. For example…

Problem Description In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.   Input The input will consist of a series of integers n, one integer per line.   Output For each case, output SUM(n) in one line, followed by a blank line.…

Given you a sequence of number a 1, a 2, ..., a n, which is a permutation of 1...n. You need to answer some queries, each with the following format: Give you two numbers L, R, you should calculate sum of gcd(a[i], a[j]) for every L <= i < j <= R.…