A hard puzzle 1097】的更多相关文章

Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin.this puzzle describes that: gave a and b,how to know…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1097 分析:简单题,快速幂取模, 由于只要求输出最后一位,所以开始就可以直接mod10. /*A hard puzzle Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 33036 Accepted Submission(s): 11821 Pr…
Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin.this puzzle describes that: gave a and b,how to know…
Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin. this puzzle describes that: gave a and b,how to know…
A hard puzzle Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 51690 Accepted Submission(s): 18916 Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,ho…
Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin.this puzzle describes that: gave a and b,how to know…
题目和1061非常相似,几乎可以复用. #include <stdio.h> ][]; int main() { int a, b; int i, j; ; i<; ++i) { buf[i][] = ; buf[i][] = i; ; j<; ++j) { buf[i][j] = buf[i][j-]*i%; ]) break; buf[i][]++; } } while (scanf("%d %d", &a, &b) != EOF) { i…
Ignatius's puzzle Problem Description Ignatius is poor at math,he falls across a puzzle problem,so he has no choice but to appeal to Eddy. this problem describes that:f(x)=5x13+13*x5+ka*x,input a nonegative integer k(k<10000),to find the minimal none…
Puzzle 面向服务/切面AOP开发框架 For .Net AOP主要实现的目的是针对业务处理过程中的切面进行提取,它所面对的是处理过程中的某个步骤或阶段,以获得逻辑过程中各部分之间低耦合性的隔离效果. 日常的产品开发中最常见的就是数据保存的功能.举例来说,现在有个用户信息数据保存的功能,我们希望在数据保存前对数据进行校验,其中现在能想到的校验就包含数据完整性校验和相同数据是否存在校验.按照传统的OOP(面向对象程序设计),我们需要定义一个IUserDataSaveService(用户数据保存…
题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5456 Description As an exciting puzzle game for kids and girlfriends, the Matches Puzzle Game asks the player to find the number of possible equations A−B=C with exactly n (5≤n≤500) matches (or stic…
one recursive approach to solve hdu 1016, list all permutations, solve N-Queens puzzle. reference: the video of stanford cs106b lecture 10 by Julie Zelenski https://www.youtube.com/watch?v=NdF1QDTRkck // hdu 1016, 795MS #include <cstdio> #include &l…
Katu Puzzle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6714   Accepted: 2472 Description Katu Puzzle is presented as a directed graph G(V, E) with each edge e(a, b) labeled by a boolean operator op (one of AND, OR, XOR) and an integ…
Multiplication Puzzle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8737   Accepted: 5468 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one…
B. Island Puzzle time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A remote island chain contains n islands, labeled 1 through n. Bidirectional bridges connect the islands to form a simple c…
题目链接:http://poj.org/problem?id=1651 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the prod…
Ignatius's puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4935    Accepted Submission(s): 3359 Problem Description Ignatius is poor at math,he falls across a puzzle problem,so he has no…
A hard puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23766    Accepted Submission(s): 8390 Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and…
                                                           M × N Puzzle Time Limit: 4000MS   Memory Limit: 131072K Total Submissions: 4112   Accepted: 1140 Description The Eight Puzzle, among other sliding-tile puzzles, is one of the famous problems…
The Problem. 求解8数码问题.用最少的移动次数能使8数码还原. Best-first search.使用A*算法来解决,我们定义一个Seach Node,它是当前搜索局面的一种状态,记录了从初始到达当前状态的移动次数和上一个状态.初始化时候,当前状态移动次数为0,上一个状态为null,将其放入优先级队列,通过不断的从优先级队列中取出Seach Node去扩展下一级的状态,直到找到目标状态.对于优先级队列中优先级的定义我们可以采用:Hamming priority function 和…
圣诞前上线的App,Tangram Puzzle 限免,大家去下载玩玩. 介绍网站:http://www.mokamisu.com/ App Store:https://itunes.apple.com/en/app/tangram-puzzle/id781360993?mt=8 惯例App的开发总结稍后放出...…
B - Hongcow Solves A Puzzle 题目连接: http://codeforces.com/contest/745/problem/B Description Hongcow likes solving puzzles. One day, Hongcow finds two identical puzzle pieces, with the instructions "make a rectangle" next to them. The pieces can be…
题目大意 构造一条闭合路线,使得路线不能相交,并且走直线的步数小于等于 S,转弯(左转和右转)的步数小于等于 T.(0≤S,T≤1000) 求一条最长的路线 做法分析 注意到,因为要求路线闭合,那么转弯的数量 T 必须大于等于 4,否则无解. 适当 YY 下:只能用偶数个 S 和偶数个 T,不然不可能构成闭合路径.怎么证明,不会... 情况1:S<2 这种情况下,我们不能使用直走的命令,只能通过不断的转弯来实现题目要求的路径,在纸上画了画,大致图形如下: T=4 时:   T=8:没有   T=…
Solve the puzzle, Save the world! Problem Description In the popular TV series Heroes, there is a tagline "Save the cheerleader, Save the world!". Here Heroes continues, "Solve the puzzle, Save the world!".Finally, alien invaders visit…
8.6 Implement a jigsaw puzzle. Design the data structures and explain an algorithm to solve the puzzle. You can assume that you have a f itsWith method which, when passed two puzzle pieces, returns true if the two pieces belong together.…
Multiplication Puzzle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8040   Accepted: 4979 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one…
题目大意:输入一颗无根树的括号序列,求这棵树的普吕弗序列. 分析思路: 1)普吕弗序列,可以参考维基百科,其做法是找出树中编号最小的叶子节点,并将此叶子节点及边删除,并输出其邻接的节点标号: 2)递归地构造树,可以使用list<int> 数组来表示一个"邻接表",以存储构造的树: 3)使用优先队列来进行删除,奈何priority_queue没有迭代器访问,只能用堆排序,取最值: 代码: #include<iostream> #include<vector&…
http://www.lydsy.com/JudgeOnline/problem.php?id=1097 首先还是我很sb....想到了分层图想不到怎么串起来,,,以为用拓扑序搞转移,,后来感到不行... QAQ 这种数据那么小,有明确的依赖性为嘛我想不到状压...(准确的说是没想到状压和分层图一起做.... 还有一个.......为什么递推不行...(还是我写挫了...老wa..)非得记忆化...... (其实记忆化的话能省点不必要的状态吧... .... 还有...和zyf一样,被卡在了..…
http://acm.hdu.edu.cn/showproblem.php?pid=4708 Rotation Lock Puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Alice was felling into a cave. She found a strange door with a number square m…
Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin.this puzzle describes that: gave a and b,how to know…
Rotation Lock Puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1836    Accepted Submission(s): 580 Problem Description Alice was felling into a cave. She found a strange door with a numbe…