UVA1316 Supermarket】的更多相关文章

题目描述 有一个商店有许多批货,每一批货又有N(0<=N<= 10^4104 )个商品,同时每一样商品都有收益 P_iPi​ ,和过期时间 D_iDi​ (1<= Pi,DiPi,Di <= 10^4104 ),一旦超过了过期时间,商品就不能再卖. 你要做的就是求出每批货最多能得到多少收益. 输入输出格式 输入格式 多组数据,每组先给出一个整数N,表示这批货的商品个数. 然后有N对数,每对数有两个用空格隔开的正整数 P_i,D_iPi​,Di​ ,表示第i个商品的收益和过期时间.相…
题目链接: https://www.luogu.org/problemnew/show/UVA1316 思路: 根据题目意思,我们需要用到贪心的思想,越晚过期的商品当然是越晚卖好.同时你假如有多个商品必须在同一天卖出,当然是卖收益多的好. 于是我们就有以下方法:首先将每个商品的过期时间按从小到大排序,同时建立一个小根堆,然后遍历这些商品. 如果商品过期时间大于堆中商品个数,说明前面还有些天是没有卖东西的,当然可以把这个商品插入堆中. 类似的,如果商品过期时间等于堆中商品个数,就比较此商品的收益和…
F - Supermarket Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1456 Appoint description:  System Crawler  (2015-11-30) Description A supermarket has a set Prod of products on sale. It earns a p…
A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx that is measured as an integral number of time units starting from the moment the sale begins. Each product takes precisely one unit…
On the way home, Karen decided to stop by the supermarket to buy some groceries. She needs to buy a lot of goods, but since she is a student her budget is still quite limited. In fact, she can only spend up to b dollars. The supermarket sells n goods…
On the way home, Karen decided to stop by the supermarket to buy some groceries. She needs to buy a lot of goods, but since she is a student her budget is still quite limited. In fact, she can only spend up to b dollars. The supermarket sells n goods…
Karen and Supermarket 感觉就是很普通的树形dp. dp[ i ][ 0 ][ u ]表示在 i 这棵子树中选择 u 个且 i 不用优惠券的最小花费. dp[ i ][ 1 ][ u ]表示在 i 这棵子树中选择 u 个且 i 用优惠券的最小花费. 注意这个转移总的合起来是O(n ^ 2)的. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk…
A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx that is measured as an integral number of time units starting from the moment the sale begins. Each product takes precisely one unit…
题目链接:http://poj.org/problem?id=1456 Time Limit: 2000MS Memory Limit: 65536K Description A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx that is measured as an integral number of tim…
题目链接 CF815C Karen and Supermarket 题解 只要在最大化数量的前提下,最小化花费就好了 这个数量枚举ok, dp[i][j][1/0]表示节点i的子树中买了j件商品 i 优惠了 / 没优惠 复杂度是n^2的 因为每次是新儿子节点的siz * 之前儿子几点的siz, 就相当于树上的节点两两匹配,这个匹配只会在lca处计算一次 代码 #include<cstdio> #include<cstring> #include<algorithm> #…