Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example: Given a = 1 and b = 2, return 3. Credits:Special thanks to @fujiaozhu for adding this problem and creating all test cases. 这道题是CareerCup上的一道原题,难道…
Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 这道题让我们求两数相除,而且规定我们不能用乘法,除法和取余操作,那么我们还可以用另一神器位操作Bit Operation,思路是,如果被除数大于或等于除数,则进行如下循环,定义变量t等于除数,定义计数p,当t的两倍小于等于被除数时,进行如下循环,t扩大一倍,p扩大一倍,然后更…
How many integers can you find Time Limit:5000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1796 Description Now you get a number N, and a M-integers set, you should find out how many integers which are sm…
Divide two integers without using multiplication, division and mod operator. 不用乘.除.求余操作,返回两整数相除的结果,结果也是整数. 假设除数是2,相除的商就是被除数二进制表示向右移动一位. 假设被除数是a,除数是b,因为不知道a除以b的商,所以只能从b,2b,4b,8b.......这种序列一个个尝试 从a扣除那些尝试的值. 如果a大于序列的数,那么a扣除该值,并且最终结果是商加上对应的二进制位为1的数,然后尝试序…
原题链接在这里:https://leetcode.com/problems/sum-of-two-integers/ 题目: Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example:Given a = 1 and b = 2, return 3. 题解: 两个数79和16 相加,不考虑进位相加得85, 只考虑进位进位是10, 85+10 = 95…
下面是今天写的几道题: 292. Nim Game You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take t…
A Simple Problem with Integers [题目链接]A Simple Problem with Integers [题目类型]线段树 成段增减+区间求和 &题解: 线段树 成段增减+区间求和 模板题 这种题真的应该理解并且可以流畅的独立码出来了 [时间复杂度]\(O(nlogn)\) &代码: #include <iostream> #include <cstdio> #include <cstring> using namespa…
Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example:Given a = 1 and b = 2, return 3. 题目要求:计算两个整型的和,但是不能用+和- 我们知道a+b为((a&b)<<1)+(a^b),因此可以用递归的方法 class Solution { public: int getSum(int a, int b)…
题目 Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT 链接 https://leetcode.com/problems/divide-two-integers/ 答案 1.int的最大值MAX_INT为power(2,31)-1 = 2147483647 2.int的最小值MIN_INT为-power(2,31) = -21…
题目链接: 传送门 A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number i…
A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 58269 Accepted: 17753 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…
How many integers can you find Time Limit:5000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Description Now you get a number N, and a M-integers set, you should find out how many integers which are small than N, that they can divi…
A Simple Problem with Integers Time Limit:5000MS Memory Limit:131072KB 64bit IO Format:%lld & %llu Description 给出了一个序列,你需要处理如下两种询问. "C a b c"表示给[a, b]区间中的值全部增加c (-10000 ≤ c ≤ 10000). "Q a b" 询问[a, b]区间中所有值的和. Input 第一行包含两个整数N, Q.1…
Divide two integers without using multiplication, division and mod operator. If it is overflow, return 2147483647 Have you met this question in a real interview? Example Given dividend = 100 and divisor = 9, return 11. LeetCode上的原题,请参见我之前的博客Divid…
Given an integer array, sort it in ascending order. Use quick sort, merge sort, heap sort or any O(nlogn) algorithm. Example Given [3, 2, 1, 4, 5], return [1, 2, 3, 4, 5]. 快速排序是排序算法中比较重要一种,也是经常容易考的一种排序算法,务必要掌握好.快排的优点是其平均时间复杂度为O(nlgn),这样在给大数据集排序的时候,…
18.3 Write a method to randomly generate a set of m integers from an array of size n. Each element must have equal probability of being chosen. 这道题让我们从一个数组中随机取出m个数字,要求每个数字被取出的概率相同,其实这道题用的是之前那道18.2 Shuffle Cards的方法,同样我们可以用递归和迭代两种方法来做,递归的思路还用的回溯法,回溯到i+…
Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example:Given a = 1 and b = 2, return 3. 一般步骤: 1.计算不用进位的位置,使用异或 2.计算进位,算数与操作,计算完后左一一位 3.如此循环 class Solution { public: int getSum(int a, int b) { int carry…
Description Elina is reading a book written by Rujia Liu, which introduces a strange way to express non-negative integers. The way is described as following: Choose k different positive integers a1, a2, …, ak. For some non-negative m, divide it by ev…
Divide Two Integers Divide two integers without using multiplication, division and mod operator. 思路: 类同 趣味算法之数学问题:题4. 两点需要注意: 1. 除数或被除数为最大负数时,转化为正数会溢出.2. divisor + divisor 可能会溢出. class Solution { public: int divide(int dividend, int divisor) { if(div…
Strange Way to Express Integers Time Limit: 1000MS Memory Limit: 131072K Total Submissions: 9472 Accepted: 2873 Description Elina is reading a book written by Rujia Liu, which introduces a strange way to express non-negative integers. The way is…
题目:Divide Two Integers Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 看讨论区大神的思路: In this problem, we are asked to divide two integers. However, we are not allowed to use division, multi…
A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 92127 Accepted: 28671 Case Time Limit: 2000MS 描述 You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operatio…
A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 53169 Accepted: 15897 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of ope…
问题描述: Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example: Given a = 1 and b = 2, return 3. 问题分析: 首先我们可以分析人们是如何做十进制的加法的,比如是如何得出5+17=22这个结果的.实际上,我们可以分成三步的:第一步只做各位相加不进位,此时相加的结果是12(个位数5和7相加不要进位是2,十位数0和…
3212: Pku3468 A Simple Problem with Integers Time Limit: 1 Sec Memory Limit: 128 MB Submit: 1278 Solved: 560 [Submit][Status][Discuss] Description You have N integers, A1, A2, - , AN. You need to deal with two kinds of operations. One type of operati…
Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 解题思路: 既然不呢个用乘除和取模运算,只好采用移位运算,可以通过设置一个length代表divisor向左的做大移位数,直到大于dividend,然后对length做一个循环递减,dividend如果大于divisor即进行减法运算,同时result加上对应的值,注意边界条…
How many integers can you find Problem Description Now you get a number N, and a M-integers set, you should find out how many integers which are small than N, that they can divided exactly by any integers in the set. For example, N=12, and M-intege…
A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 92632 Accepted: 28818 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…
Divide two integers without using multiplication, division and mod operator. 常常出现大的负数,无法用abs()转换成正数的情况 class Solution{ private: vector<long long> f; public: int bsearch(vector<long long> &a,int left,int right,long long key){ if(left > r…
