［抄题］: Given a matrix of M x N elements (M rows, N columns), return all elements of the matrix in diagonal order as shown in the below image. Example: Input: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] Output: [1,2,4,7,5,3,6,8,9] Explanation: [暴力解法]: 时间…

[LeetCode]498. Diagonal Traverse 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/diagonal-traverse/description/ 题目描述: Given a matrix of M x N elements (M rows, N columns), ret…

详见:https://leetcode.com/problems/diagonal-traverse/description/ C++: class Solution { public: vector<int> findDiagonalOrder(vector<vector<int>>& matrix) { if (matrix.empty() || matrix[0].empty()) { return {}; } int m = matrix.size(),…

Given a matrix of M x N elements (M rows, N columns), return all elements of the matrix in diagonal order as shown in the below image. Example: Input: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] Output: [1,2,4,7,5,3,6,8,9] Explanation: Note: The total…

Given a matrix of M x N elements (M rows, N columns), return all elements of the matrix in diagonal order as shown in the below image. Example: Input: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] Output: [1,2,4,7,5,3,6,8,9] Explanation: Note: The total…

题目思路 题目来源 C++实现 class Solution { public: vector<int> findDiagonalOrder(vector<vector<int>>& matrix) { if(matrix.empty()) { return {}; } vector<int> result; bool fromUp = false; /* false 自下而上 ture 自上而下*/ int a = 0; int b = 0; //…

#include<stdio.h> #include<iostream> #include<string.h> #include<algorithm> using namespace std; int main() { int n; ][]; while(cin>>n){ memset(a,,sizeof(a)); ;i<n;i++){ ;j<n;j++){ scanf("%d",&a[i][j]); }…

class Solution(object):     def convert(self, s, numRows):         if numRows==1:             return s         res = ['' for _ in range(numRows)]         # 周期         T = numRows + numRows -2         for i in range(len(s)):             t_num = i%T   …

问题:给定 n 行和 m 列的二维数组矩阵.如图所示,以 ZIG-ZAG 方式打印此矩阵. 从对称的角度来看,通过反复施加滑行反射可以从简单的图案如线段产生规则的之字形. 主要思想:算法从(0, 0)位置开始水平向右遍历,当到达(0, 1)时沿着反对角线方向左下遍历(利用一个变量控制左下右上方向),内层循环一直遍历到碰到边缘时row++,方向改为右上,沿着反对角线碰到矩阵上边缘时col++,方向变为左下遍历,知道上半部分(包括反对角线遍历完):遍历完半个矩阵(可能是子方矩阵)后,根据当前 row…

一.柱状图 1.通过obj.plot() 柱状图用bar表示,可通过obj.plot(kind='bar')或者obj.plot.bar()生成:在柱状图中添加参数stacked=True,会形成堆叠图. fig,axes = plt.subplots(2,2,figsize=(10,6)) s = pd.Series(np.random.randint(0,10,15),index = list('abcdefghijklmno')) df = pd.DataFrame(np.random.r…