LeetCode Longest Increasing Subsequence （LIS O(nlogn)）

【LeetCode Longest Increasing Subsequence （LIS O(nlogn)）】的更多相关文章

LeetCode Longest Increasing Subsequence （LIS O(nlogn)）

题意: 给一个数组,求严格递增的最长递增子序列的长度. 思路: 开销是一个额外的O(n)的数组.lower_bound(begin,end,val)的功能是:返回第一个大于等于val的地址. class Solution { public: int lengthOfLIS(vector<int>& nums) { ; int *p=new int[nums.size()]; p[]=nums[]; ; ; i<nums.size(); i++) { if(nums[i]>p…

POJ 2533 Longest Ordered Subsequence（LIS模版题）

Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 47465 Accepted: 21120 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ...…

LeetCode -- Longest Increasing Subsequence(LIS)

Question: Given an unsorted array of integers, find the length of longest increasing subsequence. For example,Given [10, 9, 2, 5, 3, 7, 101, 18],The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be m…

LeetCode OJ：Longest Increasing Subsequence（最长递增序列）

Given an unsorted array of integers, find the length of longest increasing subsequence. For example,Given [10, 9, 2, 5, 3, 7, 101, 18],The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than o…

[LeetCode] Longest Increasing Subsequence 最长递增子序列

Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than…

[LeetCode] Longest Increasing Subsequence

Longest Increasing Subsequence Given an unsorted array of integers, find the length of longest increasing subsequence. For example,Given [10, 9, 2, 5, 3, 7, 101, 18],The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Not…

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[LeetCode] Longest Increasing Subsequence 最长递增子序列

[LeetCode] Longest Increasing Subsequence

65.Longest Increasing Subsequence（最长增长子序列）

HPU第三次积分赛-D：Longest Increasing Subsequence（DP）

Poj 2533 Longest Ordered Subsequence（LIS）

Longest Increasing Subsequence（DP）