Stars(BIT树状数组)】的更多相关文章

Stars Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 30496   Accepted: 13316 Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a st…
Stars Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4052    Accepted Submission(s): 1592 Problem Description Astronomers often examine star maps where stars are represented by points on a plan…
Language:Default Stars Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 52268 Accepted: 22486 Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the…
Stars Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 54352   Accepted: 23386 Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a st…
算法学习:http://www.cnblogs.com/George1994/p/7710886.html 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1541 Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a…
Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a star be an amount of the stars that are not higher and not to the right of the given star. Astronomers wa…
一.Ultra-QuickSort(树状数组求逆序数) 题目链接(点击) Ultra-QuickSort Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 73943   Accepted: 27692 Description In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a seque…
题意:求坐标0到x间的点的个数 思路:树状数组,主要是转化,根据题意的输入顺序,保证了等级的升序,可以直接求出和即当前等级的点的个数,然后在把这个点加入即可. 注意:树状数组下标从1开始(下标为0的话会出错),所以把所有的x加1存储. #include<iostream> #include<stdio.h> #include<string.h> using namespace std; #define MAXN 32005 #define MAXL 15005 int…
绝对大坑.千万记住树状数组0好下标位置是虚拟节点.详见大白书P195.其实肉眼看也能得出,在add(有的也叫update)的点修改操作中如果传入0就会死循环.最后TLE.所以下标+1解决问题.上代码! #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <algorithm> #include <numeric> #i…
<题目链接> 题目大意: 题目给出n个点,这些点按照y坐标的升序,若y相同,则按照x的升序顺序输入,问,在这些点中,左下角的点的数量分别在0~n-1的点分别有多少个,写出它们的对应点数.  解题分析: 因为所有点是按照y坐标的升序优先给出,所以后面的点y坐标一定大于等于前面的.于是,判断该点前面有多少点满足在该点的“左下角”,只需看前面的点有几个x坐标小于当前点即可,所以,我们只需要对x坐标建一维树状数组即可求解. #include <cstdio> #include <cs…