HDU 2393 Higher Math】的更多相关文章

Higher Math Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2219    Accepted Submission(s): 1219 Problem Description You are building a house. You’d prefer if all the walls have a precise right…
#include <cstdio> #include <string> using namespace std; void swap(int& a,int& b) { int t; t=a; a=b; b=t; } int main() { int n; scanf("%d",&n); ; i<=n; i++) { printf("%s%d%s\n","Scenario #",i,"…
题意:给定三个边,判断是不是直角三角形. 析:水题,勾股定理... 代码如下: #include <iostream> #include <cstdio> #include <algorithm> #include <queue> #include <vector> #include <cstring> #include <map> using namespace std; const int maxn = 100; in…
Higher Math Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2853    Accepted Submission(s): 1525 Problem Description You are building a house. You’d prefer if all the walls have a precise right…
题目链接:HDU - 5170GTY's math problem 题目描述 Description GTY is a GodBull who will get an Au in NOI . To have more time to learn algorithm knowledge, he never does his math homework. His math teacher is very unhappy for that, but she can't do anything beca…
A Math Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 389    Accepted Submission(s): 185 Problem Description You are given a positive integer n, please count how many positive integers…
题意 f(x)=|ax3+bx2+cx+d| 求f(x)在L≤x≤R的最大值. 分析 参数有可能是0,注意分类讨论 1.当a=0时 b=0,f为一次函数(c≠0)或者常数函数(c=0),最大值点在区间端点. b≠0,f为二次函数,最大值点在区间端点或者x0=c/(2*b),当L≤x0≤R时,ans=max{f(L),f(R),f(x0)}. 2.当a≠0时,f为三次函数 最大值点在区间端点或者导函数的零点x1,x2. 注意x1,x2是否在[L,R]区间. 代码 #include<cstdio>…
暴力. $k$的$k$次方在$k=15$的时候,达到了最大不爆掉的情况. #include<bits/stdc++.h> using namespace std; long long ans[20]; long long n; long long get(long long x) { long long res = 1; long long t = x; while(x) { res = res * t; x --; } return res; } int main() { for(long…
目录 @description@ @solution@ @accepted code@ @details@ @description@ 求: \[\sum_{i=1}^{n}\sum_{j=1}^{n}gcd^k(i, j)\times lcm(i, j)\times [gcd(i, j) \in prime] \mod 10^9 + 7 \] 原题传送门. @solution@ \[\begin{aligned} ans &= \sum_{i=1}^{n}\sum_{j=1}^{n}gcd^k…
HDU 1000 A + B Problem  I/O HDU 1001 Sum Problem  数学 HDU 1002 A + B Problem II  高精度加法 HDU 1003 Maxsum  贪心 HDU 1004 Let the Balloon Rise  字典树,map HDU 1005 Number Sequence  求数列循环节 HDU 1007 Quoit Design  最近点对 HDU 1008 Elevator  模拟 HDU 1010 Tempter of th…