Financial Management Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 165062   Accepted: 61316 Description Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has deci…

与1141题相同. 时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:843 解决:502 题目描述: Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and s…

时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:939 解决:489 题目描述: Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his f…

Financial Management POJ - 1004 解题思路:水题. #include <iostream> #include <cstdio> #include <iomanip> #include <cmath> using namespace std; int main() { double sum=0.0; double now=0.0; while(cin>>now){ sum+=now; ;i<;i++){ cin&…

水两发去建模,晚饭吃跟没吃似的,吃完没感觉啊. ---------------------------分割线"水过....."------------------------------- POJ 3100 Root of the Problem http://poj.org/problem?id=3100 大意: 给定B和N,求一个数A使得A^N最接近B 太水了..... #include<cstdio> #include<cmath> int main()…

Financial Management Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 126087   Accepted: 55836 Description Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has deci…

Financial Management Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 164431   Accepted: 61085 Description Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has deci…

一. 题目 Financial Management Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 173910   Accepted: 65186 Description Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry ha…

Financial Management Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 182193   Accepted: 68783 Description Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has deci…

[POJ1004]Financial Management 试题描述 Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing pr…

Recently,i am learning some useful things about financial management by reading <Essentials of Corporate Finance> writed by Ross/Westerfield/Jordan.Now i will share with you. Chapter One : Introduction to Financial Management Traditionally,finance a…

Financial Management 时间限制:3000 ms  |  内存限制:65535 KB 难度:1   描述 Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio…

Financial Management Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 acm.hust.edu.cn/vjudge/problem/visitOriginUrl.action?id=20184 Description Michael graduated of ITESO this year and finally has a job. He's making a lot of money, but somehow never seem…

Financial Management Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 179458   Accepted: 67604 Description Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has deci…

SAP一句话入门:Material Management http://blog.vsharing.com/MilesForce/A616683.html 让我们来关注供应链上的另一个模块Material Management,即MM.物料管理.从SAP对其定义的范畴来看,它处在供应链的上中游.而广义的物料(物资或物品,是英文Material的翻译,下同)管理关注的范围则可能更多.延续上一篇的叙述风格,下面我尽量用浅显直白的语言对SAP的MM模块做一个介绍. 物料(Material)的含义极广,…

http://poj.org/problem?id=3321 http://acm.hdu.edu.cn/showproblem.php?pid=3887 POJ 3321: 题意:给出一棵根节点为1的边不一定的树,然后给出问题:询问区间和 或者 节点值更新. HDU 3887: 题意:和POJ 3321的题意差不多,只不过对每个节点询问不包含该节点的区间和 思路:今天才学了下才知道有DFS序这种东西,加上树状数组处理一下区间和 和 节点更新. DFS序大概就是我们在DFS遍历一棵树的时候,在进…

POJ 3252:Round Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10099 Accepted: 3669 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Sciss…

1.链接地址: http://poj.org/problem?id=1004 http://bailian.openjudge.cn/practice/1004 2.题目: 总时间限制: 1000ms 内存限制: 65536kB 描述 Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decid…

参考:https://www.cnblogs.com/BTMaster/p/3525008.html #include <iostream> #include <cstdio> #include <cstring> using namespace std; int main() { float a,sum; while (cin>>a)//要注意格式,能从文件读入多组数据! { sum=a; ;i<;i++) { cin>>a; sum+=…

求平均数,记得之前在杭电oj上做过一个求平均数的题目,结果因为题目是英文的,我就懵逼了 #include <stdio.h> int main() { ; double num; int i; ; i < ; ++i) { scanf("%lf",&num); sum += num; } printf("$%.2f",sum/12.0); }…

http://poj.org/problem?id=1260 Pearls Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8474   Accepted: 4236 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls…

http://poj.org/problem?id=3903 Stock Exchange Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5983   Accepted: 2096 Description The world financial crisis is quite a subject. Some people are more relaxed while others are quite anxious. J…

1.题目描述: http://poj.org/problem?id=1004 2.解题过程 这个题目咋一看很简单,虽然最终要解出来的确也不难,但是还是稍微有些小把戏在里面,其中最大的把戏就是float 输入的精度问题,比如,一种最简单最直观的的解题方案如下: #include <stdlib.h> #include <stdio.h>   int main() { int sum = 0; float cb_this_month; for(int i=0;i<12;++i)…

题目来源:http://poj.org/problem?id=1004 题目大意: Larry今年毕业并找到了工作.他开始赚很多的钱,然而他似乎总觉得不够.Larry决定好好掌控他的资产,解决他的财务问题.第一步就是找出他的钱到底发生了什么.Larry有一个银行账户,他希望知道他有多少钱.帮助Larry写一个程序,读入他过去12个月里每个月结束时的账户余额,计算出他每月平均账户余额.(实质就是求12个数的平均数.) 输入:由12行组成,每行一个正的浮点数,计到小数点后两位.表示每月结束时的账户余…

http://poj.org/problem?id=1459 题意:有np个发电站,nc个消费者,m条边,边有容量限制,发电站有产能上限,消费者有需求上限问最大流量. 思路:S和发电站相连,边权是产能上限,消费者和T相连,边权是需求上限,边的话就按题意加就好了.难点更觉得在于输入..加个空格..边数组要*2,因为有反向边. #include <cstdio> #include <algorithm> #include <iostream> #include <cs…

上一节已经学习了CLI命令行来控制JBOSS,如果想在程序中以编码方式来控制JBOSS,可以参考下面的代码,实际上在前面的文章,用代码控制Jboss上的DataSource,已经有所接触了,API与CLI是完全等价的,一个是人工敲指令,一个是代码控制,二者最终的效果一致. import com.sun.javafx.sg.PGShape; import org.jboss.as.controller.client.ModelControllerClient; import org.jboss.a…

http://poj.org/problem?id=3436 题意:题意很难懂.给出P N.接下来N行代表N个机器,每一行有2*P+1个数字 第一个数代表容量,第2~P+1个数代表输入,第P+2到2*P+1是代表输出 输入有三种情况,0,1,2.输出有0,1两种情况输入0代表不能有这个接口,1代表必须要有这个接口,2代表这个接口可有可无.输出0代表有这个接口,1代表没有这个接口.大概输出就是像插头,输入像插座,只有接口吻合才可以相连. 思路:比较简单的最大流,主要是理解题意很难,把每台机器拆成输…

http://poj.org/problem?id=2195 题意:有一个地图里面有N个人和N个家,每走一格的花费是1,问让这N个人分别到这N个家的最小花费是多少. 思路:通过这个题目学了最小费用最大流.最小费用最大流是保证在流量最大的情况下,使得费用最小. 建图是把S->人->家->T这些边弄上形成一个网络,边的容量是1(因为一个人只能和一个家匹配),边的费用是曼哈顿距离,反向边的费用是-cost. 算法的思想大概是通过SPFA找增广路径,并且找的时候费用是可以松弛的.当找到这样一条增…

http://poj.org/problem?id=3281 题意:有n头牛,f种食物,d种饮料,每头牛有fnum种喜欢的食物,dnum种喜欢的饮料,每种食物如果给一头牛吃了,那么另一个牛就不能吃这种食物了,饮料也同理,问最多有多少头牛可以吃到它喜欢的饮料和食物. 思路:一开始还以为二分匹配可以做,当然如果只有食物或者饮料其中一种就可以做.难点在于建图.看了下书,因为要保证经过牛的流量是1(每种食物对应分配给一头牛,每种饮料对应分配给一头牛,避免一头牛吃多份),所以要把牛拆成两个点.形成这样的路…

http://poj.org/problem?id=3580 题意:有6种操作,其中有两种之前没做过,就是Revolve操作和Min操作.Revolve一开始想着一个一个删一个一个插,觉得太暴力了,后来发现可以把要放到前面的一段切开,丢到前面去,就和上一题的Cut是一样的了.还有Min操作,一开始特别ZZ地想着只要找keytree的最左边就好了,然后发现并不是那样的,要维护一个 mi 值,一开始两个节点设成 INF,然后 pushup 的时候先把 val 赋给 mi,然后再和左右儿子对比.WA了…