Sequence  Accepts: 25  Submissions: 1442  Time Limit: 2000/2000 MS (Java/Others)  Memory Limit: 262144/262144 K (Java/Others) 问题描述 Soda习得了一个数列, 数列的第nn (n \ge 1)(n≥1)项是3n(n-1)+13n(n−1)+1. 现在他想知道对于一个给定的整数mm, 是否可以表示成若干项上述数列的和. 如果可以, 那么需要的最小项数是多少? 例如, 22…

Sequence  Accepts: 59  Submissions: 650  Time Limit: 2000/1000 MS (Java/Others)  Memory Limit: 65536/65536 K (Java/Others) 问题描写叙述 \ \ \ \    Lcomyn 是个非常厉害的选手,除了喜欢写17kb+的代码题,偶尔还会写数学题.他找到了一个数列: f_n=\left\{\begin{matrix} 1 ,&n=1 \\ a^b,&n=2 \\ a^bf_{…

题面太丑了,就不复制了. 题意:F1=A: F2=B: Fn=D*Fn-1+C*Fn-2+P/i:求Fn. 思路:根据P/i的值划分区间,每个区间矩阵求. 带常数的矩阵: #include<bits/stdc++.h> #define ll long long #define rep(i,a,b) for(int i=a;i<=b;i++) using namespace std; ; struct mat { ][]; mat(){memset(mp,,sizeof(mp)); } m…

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HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…

HDU 5860 Death Sequence(递推) 题目链接http://acm.split.hdu.edu.cn/showproblem.php?pid=5860 Description You may heard of the Joseph Problem, the story comes from a Jewish historian living in 1st century. He and his 40 comrade soldiers were trapped in a cave…

HDU 1005 Number Sequence(数论) Problem Description: A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multipl…

/* HDU 6078 - Wavel Sequence [ DP ] | 2017 Multi-University Training Contest 4 题意: 给定 a[N], b[M] 要求满足 a[f(1)]<a[f(2)]>a[f(3)]<a[f(4)]>a[f(5)]<a[f(6)]... b[g(i)] == a[f(i)] f(i) < f(i+1), g(i) < g(i+1) 的子序列 的数目 分析: dp[i][j][0] 表示 以a[i]…

/* HDU 6047 - Maximum Sequence [ 单调队列 ] 题意: 起初给出n个元素的数列 A[N], B[N] 对于 A[]的第N+K个元素,从B[N]中找出一个元素B[i],在 A[] 中找到一个数字A[p]满足 B[i] <= p <= N+K-1 令 A[N+K] = A[p]-p,直到A[]的长度等于2N 问 A[N+1] + A[N+2] + ... + A[N<<1] 最大是多少 分析: 将A[]中元素全部减去其下标 将B[]排序,可分析一定是从小…

HDU - 1005 Number Sequence Problem Description A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test…