暴力搜索加剪枝~ #include<bits/stdc++.h> using namespace std; ; int a[maxn]; bool visit[maxn]; vector<int> path,tmp; ; void dfs (int v) { if (tmp.size()==M) { ,liewolf=; ;i<=N;i++) { &&visit[abs(a[i])]==false) { liecnt++; if (visit[i]==true…

1148 Werewolf - Simple Version (20 分)   Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game, player #1 said: "Player #2 is a werewolf."; player #2 said: "…

Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game, player #1 said: "Player #2 is a werewolf."; player #2 said: "Player #3 is a human."; player #3…

1148 Werewolf - Simple Version (20 分) Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game, player #1 said: "Player #2 is a werewolf."; player #2 said: "P…

Source: PAT (Advanced Level) Practice Reference: [1]胡凡,曾磊.算法笔记[M].机械工业出版社.2016.7 Outline: 基础数据结构: 线性表:栈,队列,链表,顺序表 树:二叉树的建立,二叉树的遍历,完全二叉树,二叉查找树,平衡二叉树,堆,哈夫曼树 图:图的存储和遍历 经典高级算法: 深度优先搜索,广度优点搜索,回溯剪枝 贪心,并查集,哈希映射 最短路径(只考察过单源),拓扑排序(18年9月第一次涉及相关概念,未正式考过),关键路径(未…

Source: PAT 1148 Werewolf - Simple Version (20 分) Description: Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game, player #1 said: "Player #2 is a werewolf."…

题目链接:1148 Werewolf - Simple Version (20 point(s)) Description Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game, player #1 said: "Player #2 is a werewolf.";…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…

博客出处:http://blog.csdn.net/zhoufenqin/article/details/50497791 题目出处:https://www.patest.cn/contests/pat-a-practise 1001 题意:给出a+b,计算c=a+b,将c输出时每三个数加一个“,” 思路:数据范围比较小,根据特殊的数据范围,也可特殊求解,不解释 #include<iostream> #include<cstdio> #include<cstring>…

WereWolf项目 Postmortem (博客园的MarkDown编辑器好像有些问题,编号都显示1..) 设想和目标 我们的软件要解决什么问题?是否定义得很清楚?是否对典型用户和典型场景有清晰的描述? 我们的软件主要是用来解决玩狼人杀这款桌游时无牌.无法官.游戏流程不熟悉等情况的.我觉得我们对典型用户和典型场景描述的较为清楚,我们项目之前做了问卷调查,提出了一些功能,Alpha版本挑了用户较需要的几个功能重点实现,之后在Beta阶段我们将继续完善其余功能. 是否有充足的时间来做计划? 与后面…