Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target. Letters also wrap around. For example, if the target is target…

题目标签:Binary Search 题目给了我们一组字母,让我们找出比 target 大的最小的那个字母. 利用 binary search,如果mid 比 target 小,或者等于,那么移到右半边: 如果 mid 比target 大,那么移到左半边,这里要包括mid,因为mid 可能是那个要找的字母. 这里还要检查一个可能,如果 target 是 z, 那么 最小的那个字母,就是 比z 大的字母. 来覆盖这个可能性,可以用 target 比 array 里最后那个字母, 如果target大…

题目 太简单了,直接上代码: class Solution { public: char nextGreatestLetter(vector<char>& letters, char target) { int n = letters.size(); ] = {}; ;i < n; ++i){ a[letters[i]-'a']++; } )%; ; i++,i%=){ ) return (char)(i + 'a'); } } };…

problem 744. Find Smallest Letter Greater Than Target 题意:一堆有序的字母,然后又给了一个target字母,让求字母数组中第一个大于target的字母,数组是循环的,如果没有,那就返回第一个字母. solution1:注意数组已经是有序数组啦...注意mid的计算,注意最后返回的元素位置. class Solution { public: char nextGreatestLetter(vector<char>& letters,…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 线性扫描 二分查找 日期 题目地址:https://leetcode.com/problems/find-smallest-letter-greater-than-target/description/ 题目描述 Given a list of sorted characters letters containing only lowercase l…

Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target. Letters also wrap around. For example, if the target is target…

思路:二分法,时间复杂度o(logn) class Solution(object): def nextGreatestLetter(self, letters, target): """ :type letters: List[str] :type target: str :rtype: str """ left, right = 0, len(letters) - 1 while left <= right: mid = (left +…

［抄题］: Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target. Letters also wrap around. For example, if the target is t…

俩方法都是用二分查找,一个调库,一个自己写而已. 方法一,调库 static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: char nextGreatestLetter(vector<char>& letters, char target) { auto p=upper_bound(letters.begin(),letters.end(…

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,  [0,1,2,4,5,6,7] might become  [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input: [3,4,5…