Codeforces Round #323】的更多相关文章

B. Once Again... Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/582/problem/B Description You are given an array of positive integers a1, a2, ..., an × T of length n × T. We know that for any i > n it is true that ai = ai -…
C. GCD Table Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/583/problem/C Description The GCD table G of size n × n for an array of positive integers a of length n is defined by formula Let us remind you that the greatest c…
http://codeforces.com/contest/583/problem/D 原题:You are given an array of positive integers a1, a2, ..., an × T of length n × T. We know that for any i > n it is true that ai = ai - n. Find the length of the longest non-decreasing sequence of the give…
D. Once Again... time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given an array of positive integers a1, a2, ..., an × T of length n × T. We know that for any i > n it is true that …
题目链接:http://codeforces.com/contest/583/problem/C C. GCD Table time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The GCD table G of size n × n for an array of positive integers a of length n …
C. GCD Table The GCD table G of size n × n for an array of positive integers a of length n is defined by formula Let us remind you that the greatest common divisor (GCD) of two positive integers x and y is the greatest integer that is divisor of both…
A. GCD Table time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The GCD table G of size n × n for an array of positive integers a of length n is defined by formula Let us remind you that the…
div1 C 这题的是给了一个无限循环的子数组,问有多少个 (l,s)l代表起点s代表长度的循环串,使得所有的在原串中的每位都小于等于另外这个串(l<=n,1<=s<n) 像这样,我们可以枚举n的因子,类似寻找素数的那种方法去搞,在一个循环中我们就可以知道这个点可以不可以选择了,然后每次都计算一次这个区间,看有多少个符合 #include <iostream> #include <cstdio> #include <string.h> #include…
E - Superior Periodic Subarrays 好难的一题啊... 这个博客讲的很好,搬运一下. https://blog.csdn.net/thy_asdf/article/details/49406133 #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define pii pair<int,int> #de…
A[i][j]表示在循环节下标i开头j结尾的最长不减子序列,这个序列的长度为p,另外一个长度为q的序列对应的矩阵为B[i][j], 将两序列合并,新的序列对应矩阵C[i][j] = max(A[i][k]+B[k][j]).非法的情况标记为-INF,用倍增加速. #include<bits/stdc++.h> using namespace std; const int INF = 0x3f3f3f3f; ; int n; typedef int MType; struct Matrix {…