时间限制: 1 Sec 内存限制: 128 MB 5G is the proposed next telecommunications standards beyond the current 4G standards. 5G planning aims at higher capacity than current 4G, allowing a higher density of mobile broadband users, and supporting device-to- device,…

/** 题目:hdu3879 Base Station 最大权闭合子图 边权有正有负 链接:http://acm.hdu.edu.cn/showproblem.php?pid=3879 题意:给出n个地方可以建房子,给出每个地方建房子的费用,如果A,B两个地方建了房子,那么可以获得C的利润. 求建一些房子可以获得的最大利润. 思路:最大权闭合子图. n个房子与t相连,容量为费用.如果A,B两个地方建了房子,那么可以获得利润C.可以新增一个点x,s->x,cap=C; x->a,cap=INF;…

Base Station Time Limit: 2000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 3879 64-bit integer IO format: %I64d      Java class name: Main A famous mobile communication company is planning to build a new set of base statio…

In the Personal Communication Service systems such as GSM (Global System for Mobile Communications), there are typically a number of base stations spreading around the service area. The base stations are arranged in a cellular structure, as shown in…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3879 A famous mobile communication company is planning to build a new set of base stations. According to the previous investigation, n places are chosen as the possible new locations to build those new s…

经典例题,好像说可以转化成maxflow(n,n+m),暂时只可以勉强理解maxflow(n+m,n+m)的做法. 题意:输入n个点,m条边的无向图.点权为负,边权为正,点权为代价,边权为获益,输出最大获益. (最大权闭合子图:图中各点的后继必然也在图中) 构图攻略:将边看做点, 若选某条边e[i](u,v,w),则必须选点u,v.由此构成一个有向图.也符合最大权闭合子图模型. 对原本的边e[i](u,v,w)连3条边(S,n+i,w),(n+i,u,inf),(n+i,v,inf). 对原本的…

题意:给定n个带权点m条无向带权边,选一个子图,则这个子图的权值为 边权和-点权和,求一个最大的权值. 析:把每条边都看成是一个新点,然后建图,就是一个裸的最大闭合子图. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #…

将第i个用户和他需要的基站连边,转化成求二分图的最大权闭合子图. 答案=正权点之和-最小割. # include <cstdio> # include <cstring> # include <cstdlib> # include <iostream> # include <vector> # include <queue> # include <stack> # include <map> # include…

题目链接: http://acdream.info/problem?pid=1127 题目: 移动通信系统中,通信网的建立主要通过基站来完成. 基站可以分为主基站和子基站.子基站和各个移动用户进行连接,子基站必须通过主基站来和外界实现通信.主基站可以覆盖到的范围是一个圆形区域,子基站和主基站的距离小于半径r才能被该主基站覆盖到.半径r由主基站的发射功率确定. 某个区域的移动通信网,包含2个主基站和N个子基站.它们的位置都可以对应到一个整数坐标上.如果子基站至少被一个主基站覆盖,则该子基站是激活的…

http://acm.hdu.edu.cn/showproblem.php?pid=3879 http://www.lydsy.com/JudgeOnline/problem.php?id=1497 题意:给出n个点m条边,其中每个点有一个权值代表修建这个点需要耗费的钱,然后m条边里面,代表如果两个修建好的点相连的话,那么可以得到一点利润.求最大的获利. 思路:和BZOJ 1497是同一道题目.学习最大权闭合图的题目,看了一下不清楚应该怎么建图,然后只好搜一个论文来看看.http://wenku…