题目大意 求区间[L, R]中距离最大和最小的两对相邻质数.R<2^31, R-L<1e6. 总体思路 本题数据很大.求sqrt(R)的所有质数,用这些质数乘以j, j+1, j+2...k(j和k使得积属于[L,R])筛选出[L,R]中的合数,然后在[L,R]的质数中得到所求. 筛法求质数 为在O(n)的时间复杂度中求得质数,我们要使筛选时每个可能为质数的数只访问一次.我们用v[i]表示i的最小质因数.每次循环到i时,假设v[i]和小于i的质数都已经在前面求出来了,若v[i]==0,则i是个…

题目大意 给定两个数L和U,要求你求出在区间[L, U] 内所有素数中,相邻两个素数差值最小的两个素数C1和C2以及相邻两个素数差值最大的两个素数D1和D2,并且L-U<1,000,000 题解 由于1<=L< U<=2,147,483,647,直接筛肯定超时,但是题目说L-U<1,000,000,我们可以先筛选出sqrt(2147483647)(约等于46340)内的素数即可,然后再用这些素数把区间[L,U]内的合数筛选掉,最后就可以枚举答案了~~~ 代码: #includ…

题目链接:传送门 题目: Prime Distance Time Limit: 1000MS Memory Limit: 65536K Total Submissions: Accepted: Description The branch of mathematics called number theory and itself). The first prime numbers are ,,, but they quickly become less frequent. One of the…

Prime Distance Time Limit: 2 Seconds      Memory Limit: 65536 KB The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number theoreticians for thousands of years is the ques…

2017-10-03 11:29:20 writer:pprp 来源:kuangbin模板 从已经筛选好的素数中筛选出规定区间的素数 /* *prime DIstance *给出一个区间[L,U],找到相邻的距离最近的两个素数的和 *还有距离最远的两个素数 *1 <= L < U <= 2147483647 *区间长度不超过1000000 *就是要筛选出[L,U]之间的素数 */ #include <iostream> #include <cstdio> #inc…

Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13961   Accepted: 3725 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number th…

                                                Prime Distance 只会埃氏筛法的弱鸡今天读了读挑战程序设计120页,明白了求小区间内素数的方法. 突然发现挑战真的是本很好的书,很具有引导性,不过很多地方没有详细证明介绍,适用进阶选手. 题意:给你两个数,求[a,b]内相邻最近的素数对与相邻最远的素数对.但是,a,b的很大,同时b-a<=1e6. 思路:判断一个数b是否为素数只需判断i*i<=b即可,也就是说小于等于b的合数的最大素因子…

Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9944   Accepted: 2677 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number the…

题目戳这里 [题目大意] 给定一个区间[L,R],求区间内的质数相邻两个距离最大和最小的. [思路分析] 其实很简单呀,很明显可以看出来是数论题,有关于质数的知识. 要注意一下的就是L和R的数据范围都很大,所以直接跑出1-R的所有质数是不可能的,于是我们就要想办法cut掉一些时间了 然后发现跑出1-的所有质数是不会超时的,接下来就好办了,直接用这些质数去标记出[L,R]区间内的合数,这样就可以在规定时间内得到[L,R]区间内的质数了,把相邻两质数相减再比较一下就可以得出答案啦QWQ [代码实现]…

The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number theoreticians for thousands of years is the question of primality. A prime number is a number that is has no prop…