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Treasure Hunt IV Time Limit: 2 Seconds      Memory Limit: 65536 KB Alice is exploring the wonderland, suddenly she fell into a hole, when she woke up, she found there are b - a + 1 treasures labled a from b in front of her.Alice was very excited but…
Treasure Hunt Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4797   Accepted: 1998 Description Archeologists from the Antiquities and Curios Museum (ACM) have flown to Egypt to examine the great pyramid of Key-Ops. Using state-of-the-ar…
Treasure Hunt IV Time Limit: 2 Seconds      Memory Limit: 65536 KB Alice is exploring the wonderland, suddenly she fell into a hole, when she woke up, she found there are b - a + 1 treasures labled a from b in front of her. Alice was very excited but…
Treasure Hunt 大意:在一个矩形区域内.有n条线段,线段的端点是在矩形边上的,有一个特殊点,问从这个点到矩形边的最少经过的线段条数最少的书目,穿越仅仅能在中点穿越. 思路:须要巧妙的转换一下这个问题,由于从一个点到终点不可能"绕过"围墙.仅仅能穿过去,所以门是否开在中点是无所谓的,仅仅要求四周线段中点到终点的线段与墙的最少交点个数就可以.更进一步,实际上,仅仅需推断四周围墙的全部点与终点的连线与内墙的最少交点加一就可以. struct Point{ double x, y;…
Treasure Hunt time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of tel…
Treasure Hunt Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8192   Accepted: 3376 Description Archeologists from the Antiquities and Curios Museum (ACM) have flown to Egypt to examine the great pyramid of Key-Ops. Using state-of-the-ar…
H - Treasure Hunt IV Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Description Alice is exploring the wonderland, suddenly she fell into a hole, when she woke up, she found there are b - a + 1 treasures labled a from b in…
E - Treasure Hunt I Time Limit:2000MS Memory Limit:65536KB Description Akiba is a dangerous country since a bloodsucker living there. Sometimes the bloodsucker will appear and kill everyone who isn't at his hometown. One day, a brave person named CC…
题目描述 Once there was a pig, which was very fond of treasure hunting. The treasure hunt is risky, and it is inadvertently caught in the peach blossom trap. Fortunately, it has got a map of peach blossom trap. You can think of it as a matrix of R row an…
[ZOJ3626]Treasure Hunt I Time Limit: 2 Seconds      Memory Limit: 65536 KB Akiba is a dangerous country since a bloodsucker living there. Sometimes the bloodsucker will appear and kill everyone who isn't at his hometown. One day, a brave person named…
Treasure Hunt I Time Limit: 2 Seconds      Memory Limit: 65536 KB Akiba is a dangerous country since a bloodsucker living there. Sometimes the bloodsucker will appear and kill everyone who isn't at his hometown. One day, a brave person named CC finds…
A. Treasure Hunt time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of…
Treasure Hunt IV Time Limit: 2 Seconds      Memory Limit: 65536 KB Alice is exploring the wonderland, suddenly she fell into a hole, when she woke up, she found there are b - a + 1 treasures labled a from b in front of her. Alice was very excited but…
After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her. The three friends are very smart so they passe…
1066 -- Treasure Hunt 题意是,在一个金字塔中有一个宝藏,金字塔里面有很多的墙,要穿过墙壁才能进入到宝藏所在的地方.可是因为某些原因,只能在两个墙壁的交点连线的中点穿过墙壁.问最少要穿过多少墙壁才能得到宝藏. 比较容易想到的一个办法就是直接用中点构图,然后判断点与点之间是否能够直接相连,最后bfs得到最小距离. 我的代码也是这样做,结果相当险的900+ms通过. 代码如下: #include <cstdio> #include <cstring> #includ…
题目链接:http://poj.org/problem?id=1066 Time Limit: 1000MS Memory Limit: 10000K Description Archeologists from the Antiquities and Curios Museum (ACM) have flown to Egypt to examine the great pyramid of Key-Ops. Using state-of-the-art technology they are…
题目描述 Once there was a pig, which was very fond of treasure hunting. One day, when it woke up, it found itself in a strange land of treasure. As for how to come in, or how to go out, no ways to know. Sad. The good news is, it was lucky that it got the…
题意:给你一个100*100的正方形,再给你n条线(墙),保证线段一定在正方形内且端点在正方形边界(外墙),最后给你一个正方形内的点(保证不再墙上) 告诉你墙之间(包括外墙)围成了一些小房间,在小房间内可以从房间边界(墙)的中点走过这堵墙,问你从给定的点走到外墙外最少走过的墙数 题解:注意我们可以从每个房间的墙的中点走出,而不是一整条线段(墙)的中点走出.... 然后我们可以找四周的边界中的每个点与给定点的连线,再与给定的线段找相交最少的交点数就是答案 但是边界每个点是无穷多个,因此我们可以这样…
思路:枚举四边墙的门的中点,与终点连成一条线段,判断与其相交的线段的个数.最小的加一即为答案. 我是傻逼,一个数组越界调了两个小时. #include<stdio.h> #include<string.h> #include<math.h> #include<iostream> using namespace std; ; ; int sgn(double x){ ; ) ; ; } struct point{ double x,y; point(){} p…
题意: 正方形的房子,给一些墙,墙在区域内是封闭的,给你人的坐标,每穿过一道墙需要一把钥匙,问走出正方形需要多少把钥匙. 解法: 因为墙是封闭的,所以绕路也不会减少通过的墙的个数,还不如不绕路走直线,所以枚举角度,得出直线,求出与正方形内的所有墙交点最少的值,最后加1(正方形边界). 代码: #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include…
题目传送门 题意:从四面任意点出发,有若干障碍门,问最少要轰掉几扇门才能到达终点 分析:枚举入口点,也就是线段的两个端点,然后选取与其他线段相交点数最少的 + 1就是答案.特判一下n == 0的时候 /************************************************ * Author :Running_Time * Created Time :2015/10/26 星期一 16:30:26 * File Name :POJ_1066.cpp ***********…
题意:给出一个100*100的正方形区域,通过若干连接区域边界的线段将正方形区域分割为多个不规则多边形小区域,然后给出宝藏位置,要求从区域外部开辟到宝藏所在位置的一条路径,使得开辟路径所需要打通的墙壁数最少("打通一堵墙"即在墙壁所在线段中间位置开一空间以连通外界),输出应打通墙壁的个数(包括边界上墙壁).题解:枚举每一个入口,在所有的情况中取穿墙数最少的输出即可,枚举每一个入口的时候,并不用枚举每条边的中间点,直接枚举该线段的两个顶点就行(因为要经过一个墙,那么从线段的任意地方进去都…
本文出自   http://blog.csdn.net/shuangde800 题目链接: zoj-3626 题意 给一棵n个节点的树, 节点编号1~n, 每个节点有权值val[i],经过这个节点就可以获取这个价值(不能重复获得)    每一条边有一个花费值w(i,j), 表示走完i和j点的边要花费w(i,j)    现在要从k点出发,总花费值为m,问总花费不超过m的情况下并且最终要回到出发点,最多可以获取多少价值? 思路 简单树形dp.    f(i,j)表示子树i, 用花费j最多可以获得的价…
本文出自   http://blog.csdn.net/shuangde800 题目链接:zoj-3627 题意 直线上有n个城市, 第i个城市和i+1个城市是相邻的.  每个城市都有vi的金币.    Alice和Bob站在城市p, 他们每天可以选择走向一个相邻的城市, 也可以选择不走. 他们是单独行动的.    他们经过一个城市就可以获得相应的金币(不能重复获得)    作为一个队伍, 他们的最远距离不能操作M, 问T天内, 他们最多一共能拿多少金币? 思路 由于每次只能走一步,那么一定是一…
题目大意:在一个正方形的迷宫里有一些交错墙,墙的两端都在迷宫的边缘墙上面,现在得知迷宫的某个位置有一个宝藏,所以需要砸开墙来获取宝藏(只能砸一段墙的中点),问最少要砸开几面墙.   分析:这个题意刚开始理解错了,以为只能砸整面墙的中点,而实际上使一段墙的中点,也就是两个交点之间的墙,这样问题就变得比较容易了,中点的意义也就不存在了,因为所有的墙都是连接的边缘,所以如果从起点到终点连线有这堵墙,那么这堵墙一定无法绕过去,所以枚举所有的边缘点到终点有几面墙即可,注意不管怎样,边缘墙一定是要砸的.  …
http://poj.org/problem?id=1066 #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <algorithm> #define maxn 500000 using namespace std; ; <<; int t1,t2,t3,t4,t5,c; int cmp(double x) { ; ) ;…
题意: 给出三个字符串,每个字符串长度相同,给出n,要求在n轮内,每一个字符串必须改变一个字符. 问最后哪个字符串中拥有最多相同的字符,即美丽度最大. 思路: 首先,很不容易想到的一点是从a变到a,有两种方式a -> 其它 -> a,或者a -> 其它 -> 其它 -> a,即变2次或者变3次. 变3次是有意义的,比如第86个样例(wa在第86): 3 aaaaa aaaaa aaaab 答案是draw 因为第一个选一个a变3次变回a,第二个同理,第三个b到a再到b再到a就可…
题意:给你3个字符串,3个人各对自己的字符串执行n轮操作,每一次选择一个字符变为任意一个和原来不同的字符.最后问你谁能使自己的串中的任意重复子串出现的次数最大化. 显然只需关注字符而非子串. 枚举每个字符,尽力使其他字符变成它. 只有一种情况需要注意!如果字符a的出现次数等于len,并且n=1,那么你不得不将一个字符a变为其他的字符,最终最多只能有len-1个a. #include<cstdio> #include<algorithm> #include<cstring>…
嘟嘟嘟 题意看题中的图就行:问你从给定的点出发最少需要穿过几条线段才能从正方形中出去(边界也算). 因为\(n\)很小,可以考虑比较暴力的做法.枚举在边界中的哪一个点离开的.也就是枚举四周的点\((x, y)\),并和起点\((x_0, y_0)\)连成线段,求和多少条线段相交. 但是因为点可以是实数,所以不知道怎么枚举.不过想想就知道,同一个区间中的点是等价的.因此我们只要枚举线段的端点即可. 至于判断线段相交,用叉积实现:对于线段\(AB\)和\(CD\),如果\((\overrightar…
#include<stdio.h> #include<math.h> #include<stdlib.h> #define eps 1e-8 #define zero(x) (((x)>0 ? (x):(-x))<eps) #define INF 0x3f3f3f3f struct Point { double x,y; }tre,point[],tp; struct Line { Point a,b; }line[]; double xmult(Point…