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THE MATRIX PROBLEM Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 41 Accepted Submission(s): 14   Problem Description You have been given a matrix CN*M, each element E of CN*M is positive and no…
THE MATRIX PROBLEM Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8693    Accepted Submission(s): 2246 Problem Description You have been given a matrix CN*M, each element E of CN*M is positive…
THE MATRIX PROBLEM Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5437    Accepted Submission(s): 1372 Problem Description You have been given a matrix CN*M, each element E of CN*M is positive…
THE MATRIX PROBLEM Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7819    Accepted Submission(s): 2019 Problem Description You have been given a matrix CN*M, each element E of CN*M is positive…
You have been given a matrix C N*M, each element E of C N*M is positive and no more than 1000, The problem is that if there exist N numbers a1, a2, … an and M numbers b1, b2, …, bm, which satisfies that each elements in row-i multiplied with ai and e…
You have been given a matrix C N*M, each element E of C N*M is positive and no more than 1000, The problem is that if there exist N numbers a1, a2, - an and M numbers b1, b2, -, bm, which satisfies that each elements in row-i multiplied with ai and e…
题目链接:https://cn.vjudge.net/contest/276233#problem/H 题目大意:对于给定的矩阵  每一行除以ai  每一列除以bi 之后 数组的所有元素都还在那个L-R范围之内,a[i]和b[j]是不知道的,然后问你是否有这样的数组a和数组b满足条件. 具体思路:我们可以写出这样的等式, L<=Map[i][j]*a[i]/b[j]<=R, 然后继续化简 L/Map[i][j]<=a[i]/b[j]<=R/Map[i][j], 然后两边同时取log…
题意: 给一个n*m矩阵,每个格子上有一个数字a[i][j],给定L和U,问:是否有这样两个序列{a1...an}和{b1...bn},满足 L<=a[i][j]*ai/bj<=U .若存在输出yes,否则no. 思路: 能够得到的是一堆不等式,那么可以用最短路来解决差分约束系统.但是a[i][j]*ai/bj<=U是除的,得提前变成减的才行.可以用对数log来解决,先不管a[i][j],logai-logbj<=U不就行了?可以得到: (1)logai - logbj<=U…
题意:给定一个最大400*400的矩阵,每次操作可以将某一行或某一列乘上一个数,问能否通过这样的操作使得矩阵内的每个数都在[L,R]的区间内. 析:再把题意说明白一点就是是否存在ai,bj,使得l<=cij*(ai/bj)<=u (1<=i<=n,1<=j<=m)成立. 首先把cij先除到两边去,就变成了l'<=ai/bj<=u',由于差分约束要是的减,怎么变成减法呢?取对数呗,两边取对数得到log(l')<=log(ai)-log(bj)<=l…
题目请戳这里 题目大意:给一个n*m的矩阵,求是否存在这样两个序列:a1,a2...an,b1,b2,...,bm,使得矩阵的第i行乘以ai,第j列除以bj后,矩阵的每一个数都在L和U之间. 题目分析:比较裸的差分约束.考虑那2个序列,可以抽象出m+n个点.乘除法可以通过取对数转换为加减法.然后就可以得到约束关系: 对于矩阵元素cij,有log(L) <= log(cij) + ai - bj <= log(U),整理可得: ai - bj <= log(U) - log(cij),n+…
差分约束系统. 根据题意,可以写出不等式 L <= (Xij * Ai) / Bj <= U 即 Ai/Bj<=U/Xij和Ai/Bj>=L/Xij 由于差分约束系统是减法..除法变减法可以用对数来解决. 两个式子两边取对数,可以写成log(Ai)-log(Bj)<=log(U/Xij)和log(Ai)-log(Bj)>=log(L/Xij) log(Ai)和log(Bj)看作两个节点.编号分别为i和n+j,建立有向图,判断有没有负环存在.  if(summ[hh]&g…
关于$f(x)$的条件,将$C=A\times B$代入,即$\sum_{i=1}^{n}\sum_{j=1}^{n}\sum_{k=1}^{r}A_{i,k}B_{k,j}=x$ 调换枚举顺序,即$\sum_{k=1}^{r}(\sum_{i=1}^{n}A_{i,k})(\sum_{j=1}^{n}B_{k,j})=x$ 显然每一部分的值都是独立的,因此令$G_{x}$​​为$(\sum_{i=1}^{n}A_{i,k})(\sum_{j=1}^{n}B_{k,j})=x$​​的方案数,枚举…
54. Spiral Matrix Problem's Link ---------------------------------------------------------------------------- Mean: 顺时针漩涡状打印二维数组的值. analyse: 控制四个边界即可. Time complexity: O(N) view code );        );        ;        )        ));        ;;;}/* */…
Tom and matrix Problem's Link:   http://acm.hdu.edu.cn/showproblem.php?pid=5226 Mean: 题意很简单,略. analyse: 直接可以用Lucas定理+快速幂水过的,但是我却作死的用了另一种方法. 方法一:Lucas定理+快速幂水过 方法二:首先问题可以转化为求(0,0),(n,m)这个子矩阵的所有数之和.画个图容易得到一个做法,对于n<=m,答案就是2^0+2^1+...+2^m=2^(m+1)-1,对于n>m…
Ilya and Matrix Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 313C Description Ilya is a very good-natured lion. He likes maths. Of all mathematical objects, his favourite one is matri…
matrix Problem Description Given a matrix with n rows and m columns ( n+m is an odd number ), at first , you begin with the number at top-left corner (1,1) and you want to go to the number at bottom-right corner (n,m). And you must go right or go dow…
转自:http://blog.csdn.net/shahdza/article/details/7779273 最短路 [HDU] 1548 A strange lift基础最短路(或bfs)★2544 最短路 基础最短路★3790 最短路径问题基础最短路★2066 一个人的旅行基础最短路(多源多汇,可以建立超级源点和终点)★2112 HDU Today基础最短路★1874 畅通工程续基础最短路★1217 Arbitrage 货币交换 Floyd (或者 Bellman-Ford 判环)★124…
转自——http://blog.csdn.net/qwe20060514/article/details/8112550 =============================以下是最小生成树+并查集======================================[HDU]1213   How Many Tables   基础并查集★1272   小希的迷宫   基础并查集★1325&&poj1308  Is It A Tree?   基础并查集★1856   More i…
Intervals Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5488    Accepted Submission(s): 1999 Problem Description You are given n closed, integer intervals [ai, bi] and n integers c1, ..., cn.…
=============================以下是最小生成树+并查集====================================== [HDU] How Many Tables 基础并查集★ 小希的迷宫 基础并查集★ &&poj1308 Is It A Tree? 基础并查集★ More is better 基础并查集★ Constructing Roads 基础最小生成树★ 畅通工程 基础并查集★ 还是畅通工程 基础最小生成树★ 畅通工程 基础最小生成树★ 畅通…
在洛谷上复制的题目! P3154 [CQOI2009]循环赛 题目描述 n队伍比赛,每两支队伍比赛一次,平1胜3负0. 给出队伍的最终得分,求多少种可能的分数表. 输入输出格式 输入格式: 第一行包含一个正整数n,队伍的个数.第二行包含n个非负整数,即每支队伍的得分. 输出格式: 输出仅一行,即可能的分数表数目.保证至少存在一个可能的分数表. 输入输出样例 输入样例#1: 复制 6 5 6 7 7 8 8 输出样例#1: 复制 121 说明 N<=8 就是一个很暴力的搜索,然而在$vjudge$…
THE MATRIX PROBLEM Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8418    Accepted Submission(s): 2179 Problem Description You have been given a matrix CN*M, each element E of CN*M is positive…
THE MATRIX PROBLEM Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8016    Accepted Submission(s): 2092 Problem Description You have been given a matrix CN*M, each element E of CN*M is positive…
[图论01]最短路 Start Time : 2018-01-02 12:45:00    End Time : 2018-01-23 12:45:00 Contest Status : Running Current System Time : 2018-01-12 14:39:34 Solved Problem ID Title Ratio(Accepted / Submitted)   1001 最短路 51.85%(70/135)   1002 King 46.67%(35/75)  …
=============================以下是最小生成树+并查集====================================== [HDU] 1213 How Many Tables 基础并查集★ 1272 小希的迷宫 基础并查集★ 1325&&poj1308 Is It A Tree? 基础并查集★ 1856 More is better 基础并查集★ 1102 Constructing Roads 基础最小生成树★ 1232 畅通工程 基础并查集★ 123…
出处:http://blog.csdn.net/shahdza/article/details/7779273 最短路 [HDU] 1548    A strange lift基础最短路(或bfs)★ 2544    最短路  基础最短路★ 3790    最短路径问题基础最短路★ 2066    一个人的旅行基础最短路(多源多汇,可以建立超级源点和终点)★ 2112    HDU Today基础最短路★ 1874    畅通工程续基础最短路★ 1217    Arbitrage   货币交换…
[HDU] 1548 A strange lift 根蒂根基最短路(或bfs)★ 2544 最短路 根蒂根基最短路★ 3790 最短路径题目 根蒂根基最短路★ 2066 一小我的观光 根蒂根基最短路(多源多汇,可以建树超等源点和终点)★ 2112 HDU Today 根蒂根基最短路★ 1874 通顺工程续 根蒂根基最短路★ 1217 Arbitrage   货币互换 Floyd (或者 Bellman-Ford 判环)★ 1245 Saving James Bond 策画几何+最短路★ 1317…
=============================以下是最小生成树+并查集====================================== [HDU] 1213 How Many Tables 基础并查集★ 1272 小希的迷宫 基础并查集★ 1325&&poj1308 Is It A Tree? 基础并查集★ 1856 More is better 基础并查集★ 1102 Constructing Roads 基础最小生成树★ 1232 畅通工程 基础并查集★ 123…
@http://www-cs-faculty.stanford.edu/people/karpathy/cvpr2015papers/ CVPR 2015 papers (in nicer format than this) maintained by @karpathy NEW: This year I also embedded the (1,2-gram) tfidf vectors of all papers with t-sne and placed them in an interf…
其实自己只会做很简单的题,有时都不想写解题报告,觉得不值得一写,但是又想到今后也许就不会做ACM了,能留下来的东西只有解题报告了,所以要好好写,很渣的题也要写,是今后的纪念. B - B Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 313A Description Ilya is a very clever lion,…