POJ 2593 Max Sequence】的更多相关文章

d(A) = max{sum(a[s1]..a[t1]) + sum(a[s2]..a[t2]) | 1<=s1<=t1<s2<=t2<=n} 即求两个子序列和的和的最大值. 为单个区间子序列和的最大值的变形. 左边的从左向右扫描,而右边的从右向左扫描即可. #include<cstdio> #include<algorithm> using namespace std; const int MAXN=50000+10; int left[MAXN],…
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 17678   Accepted: 7401 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N).  You should output S.  Input The input will consist of several test cases.…
题目链接:http://poj.org/problem?id=2593 思路分析:该问题为求给定由N个整数组成的序列,要求确定序列A的2个不相交子段,使这m个子段的最大连续子段和的和最大. 该问题与poj 2479相同,解法也一样: 代码如下: #include <cstdio> #include <iostream> using namespace std; + ; int arr[MAX_N], dp_s[MAX_N], dp_r[MAX_N]; int arr_num; in…
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16329   Accepted: 6848 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N). You should output S.  Input The input will consist of several test cases. F…
id=1699" target="_blank" style="">题目链接:poj 1699 Best Sequence 题目大意:给定N个DNA序列,问说最少多长的字符串包括全部序列. 解题思路:AC自己主动机+状压DP,先对字符串构造AC自己主动机.然后在dp[s][i]表示匹配了s.移动到节点i时候的最短步数. #include <cstdio> #include <cstring> #include <queu…
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 18511   Accepted: 7743 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N). You should output S.  Input The input will consist of several test cases. F…
[poj P1141] Brackets Sequence Time Limit: 1000MS   Memory Limit: 65536K   Special Judge Description Let us define a regular brackets sequence in the following way: 1. Empty sequence is a regular sequence. 2. If S is a regular sequence, then (S) and […
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16850   Accepted: 7054 Description Give you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N). You should output S. Input The input will consist of several test cases. Fo…
一.题目大意 有这样一个序列包含S1,S2,S3...SK,每一个Si包括整数1到 i.求在这个序列中给定的整数n为下标的数. 例如,前80位为11212312341234512345612345671234567812345678912345678910123456789101112345678910,第8位为2. 二.题解 动手做这道题之前要了解所求的是第n位而不是某一个Si中的第几个数,一位数占一位,两位数占两位,三位占三位...由于每一组都比前一组多一个数,如果这个数是一位数,则该组数的…
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