HDU1005 数列找规律】的更多相关文章

Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case…
题目:Click here 题意:给定数列满足求f(n)mod(1e9+7). 分析:规律题,找规律,特别注意负数取mod. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; ; ; int x, y, n; ]; int main() { while( ~scanf…
1002: [FJOI2007]轮状病毒 Time Limit: 1 Sec  Memory Limit: 162 MBSubmit: 2234  Solved: 1227[Submit][Status] Description 给定n(N<=100),编程计算有多少个不同的n轮状病毒. Input 第一行有1个正整数n. Output 将编程计算出的不同的n轮状病毒数输出 Sample Input 3 Sample Output 16 HINT Source 基尔霍夫矩阵总算编出来了,这道题考…
P1176奇怪的数列 Accepted 标签:[显示标签] 背景 一天.学军数学小组的成员遇到了一个奇怪的数列,正巧信息小组的你碰到了他们. 于是他们把这个数列展示给你-- 描写叙述 这个数列是这种: 0,1,3,2,6,7,5,4,12,13,15,14,10,11,9,8,24,25,27,26,30,31-- 先细致研究一下这个数列的规律. 如今他们请你编写一个程序,要求找出数n在此数列中的位置序号k. 格式 输入格式 输入数据仅仅有一行,为数 n (n<=2^31-1) 输出格式 输出数…
多校10 1002 HDU 6172 Array Challenge 题意 There's an array that is generated by following rule. \(h_0=2,h_1=3,h_2=6,h_n=4h_{n-1}+17h_{n-2}-12h_{n-3}-16\) And let us define two arrays bnandan as below. $ b_n=3h_{n+1} h_n+9h_{n+1} h_{n-1}+9h_n^2+27h_n h_{n…
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 198316    Accepted Submission(s): 49744 Problem Description A number sequence…
Exclusive or 题目链接: http://acm.hust.edu.cn/vjudge/contest/121336#problem/J Description Given n, find the value of Note: ♁ denotes bitwise exclusive-or. Input The input consists of several tests. For each tests: A single integer n (2≤n<10^500). Output…
逐渐发现找规律的美妙之处啦,真不错,用普通方法解决很久或者很麻烦的问题,找到规律就很方便,算法最主要还是思想 Description There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).    Input Input consists of a sequence of lines, each containing an integer n. (n < 1,…
Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case co…
P2144 [FJOI2007]轮状病毒 题目描述 轮状病毒有很多变种.许多轮状病毒都是由一个轮状基产生.一个n轮状基由圆环上n个不同的基原子和圆心的一个核原子构成.2个原子之间的边表示这2个原子之间的信息通道,如图1. n轮状病毒的产生规律是在n轮状基中删除若干边,使各原子之间有唯一一条信息通道.例如,共有16个不同的3轮状病毒,入图2所示. 给定n(N<=100),编程计算有多少个不同的n轮状病毒. 输入输出格式 输入格式: 第一行有1个正整数n. 输出格式: 将编程计算出的不同的n轮状病毒…