Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…

题目内容 题目来源:LeetCode Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Write a function to determine if a given target is in the array. The array may contain…

题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no du…

题目 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no dup…

题目内容 本题来源LeetCode Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwi…

思路:每次取中间元素,一定有一半有序,另一半部分有序,有序的部分进行二分查找,部分有序的部分递归继续处理. class Solution { public: ; int middleSearch(int left, int right,vector<int>& nums, int target){//二分查找 || left < ); if(nums[left] == target)return left; ; if(nums[mid] == target)return mid;…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 题解:如果没有重复的元素,那么就可以根据target是否在某一半而扔掉另外一半.但是如果有…

LeetCode:Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, other…

做Leetcode题有一段时间了,但都是断断续续的,到现在才做了30题左右,感觉对自己来说还是有点难度的.希望自己能继续坚持下去,在校招前能解决超过一百题吧. 其实这些题就是用来训练你的解题思路的,做多了的话,才能在校招时面对编程题目,能立即有一个解题的流程,知道这是哪一种类型的题目,一般用什么样的套路,思路会很清晰,比如基础的字符串,数组操作会用到一些排序算法,还有一类是算法思想的题目,比如DP(动态规划),分治,回溯法,贪心等等,多练,多思考,多总结. ‘庖丁解牛,恢恢乎游刃有余’,无他,唯…

Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 原题链接:https://oj.leetcode.com/problems/search…