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1037 Magic Coupon (25 分) The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the sh…
1037 Magic Coupon(25 分) The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the sho…
1037 Magic Coupon (25 分)   The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the…
https://pintia.cn/problem-sets/994805342720868352/problems/994805451374313472 The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times…
The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…
题目 The magic shop in Mars is ofering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also ofers some bonu…
The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…
The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…
#include<iostream> #include<vector> #include<stdio.h> #include<algorithm> using namespace std; int cmp(int a,int b) { return a<b; } int main() { int n,i,j,tem; while(scanf("%d",&n)!=EOF) { getchar(); vector<int&…
题目说了那么多,就是给你两个序列,分别选取元素进行一对一相乘,求得到的最大乘积. 将两个序列的正和负数分开,排个序,然后分别将正1和正2前面的相乘,负1和负2前面的相乘,累加和即可. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <vector> using namespa…