Periodic Strings UVA - 455】的更多相关文章

​ A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repetitions of the string &quo…
Periodic Strings 模板 题意分析 判断字符串的最小周期 代码总览 /* Title:UVA.455 Author:pengwill Date:2016-12-16 */ #include <iostream> #include <cstdio> #include <cstring> using namespace std; char str[100]; int main() { int n; scanf("%d",&n); w…
UVa OJ 455 Periodic Strings A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repe…
 Periodic Strings  A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repetitions o…
题意:给出一个字符串,找出它的最小的周期,枚举从1到len的周期,看是否满足. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ]; int main() { int ncase,t,i,k,j,len; scanf("%d",&ncase); while(ncase--) { scanf(…
1.题目大意 求一个长度不超过80的字符串的最小周期. 2.思路 非常简单,基本就是根据周期的定义做出来的,几乎不需要过脑. 3.应该注意的地方 (1) 最后输出的方式要注意,不然很容易就PE了.不过个人认为,其实这题Sample Output给的不好 (2) 注意输出的要求是最小周期 4.代码 #include"stdio.h" #include"string.h" #define maxn 80 int main() { int T,m,i,j,flag; ch…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 枚举 [代码] #include <bits/stdc++.h> using namespace std; const int N = 100; char s[N]; int len; bool check(int L) { if (len%L != 0) return false; for (int i = L; i < len; i++) if (s[i] != s[i%L]) return false; retur…
解题思路: 对一个字符串求其最小周期长度,那么,最小周期长度必定是字符串长度的约数,即最小周期长度必定能被字符串长度整除 其次,对于最小周期字符串,每位都能对应其后周期字串的每一位, 即 ABC  ABCABC (345678)->%其字串长度3 012  3%3 4%3 5%3  6%3 7%3  8%3   0      1     2        0      1       2 if(a[j]!=a[j%3])说明不对应,不是周期,进行下一位扫描. AC Code: #include<…
#include <stdio.h>#include <string.h> int main(){    int T, k, len;    char str[81], *p, *q, *end;    scanf("%d", &T);    while (T--)    {        scanf("%s", str);        len = strlen(str);        end = str+len;        …
最小周期可以用%枚举 #include <iostream> #include <string> #include <cstring> #include <cstdlib> #include <cstdio> #include <cmath> #include <algorithm> #include <stack> #include <cctype> using namespace std; #d…