题目链接:https://vjudge.net/problem/POJ-3080 Blue Jeans Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 19152   Accepted: 8524 Description The Genographic Project is a research partnership between IBM and The National Geographic Society that…
Blue Jeans DescriptionThe Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IBM researcher, you hav…
Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IBM researcher, you have been tas…
Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated.  As an IBM researcher, you have been ta…
Blue Jeans Time Limit: 1000MS   Memory Limit: 65536K Total Submissions:21746   Accepted: 9653 Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousan…
题意:给你n个字符串,问你这n个串的最长公共子串 解题思路:暴力枚举任意一个字符串的所有子串,然后暴力匹配,和hdu1238差不多的思路吧,这里用string解决的: 代码: #include<iostream> #include<string> #include<cstdio> #include<algorithm> using namespace std; string t; int main() { int n; string a[4050]; ios…
题意:求n个串的字典序最小的最长公共子串. 解法:枚举第一个串的子串,与剩下的n-1个串KMP匹配,判断是否有这样的公共子串.从大长度开始枚举,找到了就break挺快的.而且KMP的作用就是匹配子串,近乎O(n)的速度,很快. P.S.对于字符串要仔细!!! #include<cstdio> #include<cstdlib> #include<cstring> #include<iostream> using namespace std; ; int n;…
The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IBM researcher, you have been tasked with wri…
题目链接:http://poj.org/problem?id=3080 题目大意:给你N个长度为60的字符串(N<=10),求他们的最长公共子串(长度>=3). 题目分析:KMP字符串匹配基础题.直接枚举第1个字符串的所有子串,判断这个子串是否出现在另外N-1个串中. 实现代码如下: #include <cstdio> #include <string> #include <iostream> #include <algorithm> #incl…
题目大意 求N个字符串的最长公共字串 题解 和POJ1226做法一样...注意是字典序最小的...WA了一次 代码: #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; #define MAXN 65 char p[MAXN],T[MAXN][MAXN]; int f[MAXN]; void getfail(cha…