Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 这道题要求用先序和中序遍历来建立二叉树,跟之前那道Construct Binary Tree from Inorder and Postorder Traversal 由中序和后序遍历建立二叉树原理基本相同,针对这道题,由于先…
Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what "{1,#,2,3}" means? > re…
题目: 思路: 这题是比较典型的树的遍历问题,思路就是将中序遍历作为位置的判断依据,假设有个节点A和它的父亲Afa,那么如果A和Afa的顺序在中序遍历中是先A后Afa,则A是Afa的左儿子,否则是右儿子. 用for遍历一遍所有的节点,让每一个节点都连接到它的父亲,最后从根节点开始访问即可. 代码: // // main.cpp // Tree // // Created by wasdns on 16/12/19. // Copyright ? 2016年 wasdns. All rights…
很坑的一道题,读了半天才读懂题,手忙脚乱的写完(套上模板+修改模板),然后RE到死…… 题意: 题面上告诉了我们这是一棵二叉树,然后告诉了我们它的先序遍历,然后,没了……没了! 反复读题,终于在偶然间注意到了这一句——"Not only that, when numbering the rooms, they always number the room number from the east-most position to the west." 它告诉我们,东边的点总是比西边的点…
题目: Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 说明:1)下面有两种实现:递归(Recursive )与非递归(迭代iterati…