276. Paint Fence篱笆涂色】的更多相关文章

[抄题]: There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color.  划重点 Return the total number of ways you can paint the fence.…
题目: There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. Note:n…
House Robber:不能相邻,求能获得的最大值 House Robber II:不能相邻且第一个和最后一个不能同时取,求能获得的最大值 House Robber III:二叉树下的不能相邻,求能获得的最大值 Paint House:用3种颜色,相邻的房屋不能用同一种颜色,求花费最小 Paint House II:用k种颜色,相邻的房屋不能用同一种颜色,求花费最小Paint Fence:用k种颜色,相邻的可以用同一种颜色,但不能超过连续的2个,求有多少种可能性 198. House Robb…
There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. Note:n and…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 日期 题目地址:https://leetcode-cn.com/problems/sum-of-digits-in-the-minimum-number/ 题目描述 There is a fence with n posts, each post can be painted with one of the k colors. You hav…
Problem: There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. N…
1260: [CQOI2007]涂色paint Time Limit: 30 Sec  Memory Limit: 64 MBSubmit: 1147  Solved: 698[Submit][Status][Discuss] Description 假设你有一条长度为5的木版,初始时没有涂过任何颜色.你希望把它的5个单位长度分别涂上红.绿.蓝.绿.红色,用一个长度为5的字符串表示这个目标:RGBGR. 每次你可以把一段连续的木版涂成一个给定的颜色,后涂的颜色覆盖先涂的颜色.例如第一次把木版涂成…
1260: [CQOI2007]涂色paint Time Limit: 30 Sec  Memory Limit: 64 MBSubmit: 893  Solved: 540[Submit][Status][Discuss] Description 假设你有一条长度为5的木版,初始时没有涂过任何颜色.你希望把它的5个单位长度分别涂上红.绿.蓝.绿.红色,用一个长度为5的字符串表示这个目标:RGBGR. 每次你可以把一段连续的木版涂成一个给定的颜色,后涂的颜色覆盖先涂的颜色.例如第一次把木版涂成R…
区间dp.. dp( l , r ) 表示让 [ l , r ] 这个区间都变成目标颜色的最少涂色次数. 考虑转移 : l == r 则 dp( l , r ) = 1 ( 显然 ) s[ l ] == s[ l + 1 ] 则 dp( l , r ) = dp( l + 1 , r )     s[ r ] == s[ r - 1 ] 则 dp( l , r ) = dp( l , r - 1 )  因为只要在涂色时多涂一格就行了, 显然相等 , 所以转移一下之后更好做 s[ l ] == s…
BZOJ_1260_[CQOI2007]涂色paint _区间DP 题意: 假设你有一条长度为5的木版,初始时没有涂过任何颜色.你希望把它的5个单位长度分别涂上红.绿.蓝.绿.红色,用一个长度为5的字符串表示这个目标:RGBGR. 每次你可以把一段连续的木版涂成一个给定的颜色,后涂的颜色覆盖先涂的颜色.例如第一次把木版涂成RRRRR,第二次涂成RGGGR,第三次涂成RGBGR,达到目标. 用尽量少的涂色次数达到目标. 分析: f[i][j]表示从i到j染色最少需要多少次 如果a[i]==a[j]…