680. Valid Palindrome II[easy] Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You co…

problem 680. Valid Palindrome II solution: 不理解判断函数中的节点的问题... class Solution { public: bool validPalindrome(string s) { , right = s.size()-; while(left<right) { if(s[left]!=s[right]) { ) || isValid(s, left+, right);//err.. } left++; right--; } return…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. 思…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. N…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. N…

［抄题］: Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. N…

Difficulty:easy  More:[目录]LeetCode Java实现 Description https://leetcode.com/problems/valid-palindrome-ii/ Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双指针 思路来源 初版方案 进阶方案 日期 题目地址:https://leetcode.com/problems/valid-palindrome-ii/description/ 题目描述 Given a non-empty string s, you may delete at most one character. Judge whether y…

题目:给定一个字符串,在最多删除一个字符的情况下,判断这个字符串是不是回文字符串. 思路:回文字符串,第一想到的就是使用两个指针,前后各一个,当遇到前后字符不一致的时候,有两种情况,删除前面字符或者删除后面字符.由于删除一个字符后剩下的仍旧是字符串,可以直接递归处理了.然后用一个flag,当达到2时,就可以递归结束了. 代码如下: class Solution(object): def isPalindrome(self, s, left, right, flag): while left <…