mycode   time limited def searchMatrix(matrix, target): def deal(data): if not data: return False row = len(data) col = len(data[0]) #print('row,col',row,col) for r in range(row): for c in range(col): #print(r,c) if data[r][c] == target: return True…

74. Search a 2D Matrix 整个二维数组是有序排列的,可以把这个想象成一个有序的一维数组,然后用二分找中间值就好了. 这个时候需要将全部的长度转换为相应的坐标,/col获得x坐标,%col获得y坐标 class Solution { public: bool searchMatrix(vector<vector<int>>& matrix, int target) { int row = matrix.size(); ) return false; ].s…

Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascendin…

Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascendin…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/search-a-2d-matrix/description/ 题目描述 Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the follow…

1.问题描写叙述 写一个高效的算法.从一个m×n的整数矩阵中查找出给定的值,矩阵具有例如以下特点: 每一行从左到右递增. 每一列从上到下递增. 2. 方法与思路 2.1 二分查找法 依据矩阵的特征非常easy想到二分法,可是这是一个二维的矩阵,怎样将问题转化为一维是关键.实际上我们能够依据矩阵的第一列确定值可能所在的行的范围(limu,limd),当中limu=0,使得matrix[0][0]≤matrix[i][0]≤matrix[limd][0],i∈[0,limd]. 而确定limd的值能…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

题目如下:这两个题目可以用同样的代码来解答,因此就合并在一起了. 题目一: 题目二: 解题思路:两个题目的唯一区别在于第二个题目下一行的最小值不一定会小于前一行的最大值.但是不管怎么样我们可以确定的是,如果某一行的最小值都比target要大,那么这一行之后的值都比target要大.如果target介于某一行的最小值和最大值之间,那么target有可能在这一行.至于如何判断target是否存在,因为数组有序,用二分查找即可. 代码如下: class Solution(object): def se…

编写一个高效的算法来搜索 m x n 矩阵中的一个目标值.该矩阵具有以下特性:    每行的元素从左到右升序排列.    每列的元素从上到下升序排列.例如,考虑下面的矩阵:[  [1,   4,  7, 11, 15],  [2,   5,  8, 12, 19],  [3,   6,  9, 16, 22],  [10, 13, 14, 17, 24],  [18, 21, 23, 26, 30]]给定目标值 target = 5, 返回 true.给定目标值 target = 20, 返回…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

一句话思路:从左下角开始找.复杂度是o(m+n). 一刷报错: 应该是一个while循环中有几个条件判断语句,而不是每个条件判断语句里去加while,很麻烦 数组越界了.从0开始,y的最大条件应该是<n,不是<n 风格上:++ -- 都是一个数字的一元运算,不用加空格 超时了.循环体结构: while (x >= 0 && y <= n) { if (matrix[x][y] == target) { count ++; } else if (matrix[x][y…

240. 搜索二维矩阵 II 240. Search a 2D Matrix II 题目描述 编写一个高效的算法来搜索 m x n 矩阵 matrix 中的一个目标值 target.该矩阵具有以下特性: 每行的元素从左到右升序排列. 每列的元素从上到下升序排列. 每日一算法2019/6/9Day 37LeetCode240. Search a 2D Matrix II 示例: 现有矩阵 matrix 如下: [   [1, 4, 7, 11, 15],   [2, 5, 8, 12, 19],…

Write an efficient algorithm that searches for a value in an m x n matrix, return the occurrence of it. This matrix has the following properties: Integers in each row are sorted from left to right. Integers in each column are sorted from up to bottom…

Leetcode之二分法专题-240. 搜索二维矩阵 II(Search a 2D Matrix II) 编写一个高效的算法来搜索 m x n 矩阵 matrix 中的一个目标值 target.该矩阵具有以下特性: 每行的元素从左到右升序排列. 每列的元素从上到下升序排列. 示例: 现有矩阵 matrix 如下: [ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23…

74. 搜索二维矩阵 74. Search a 2D Matrix 题目描述 编写一个高效的算法来判断 m x n 矩阵中,是否存在一个目标值.该矩阵具有如下特性: 每行中的整数从左到右按升序排列. 每行的第一个整数大于前一行的最后一个整数. LeetCode74. Search a 2D Matrix中等 示例 1: 输入: matrix = [   [1, 3, 5, 7],   [10, 11, 16, 20],   [23, 30, 34, 50]] target = 3 输出: tru…

Question: Search a 2D Matrix Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the la…

Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix, return the occurrence of it. This matrix has the following properties: Integers in each row are sorted from left to right. Integers in each column are so…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

原题链接在这里:https://leetcode.com/problems/search-a-2d-matrix-ii/ Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integer…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous ro…

Description: Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from to…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

题目描述 编写一个高效的算法来搜索 m x n 矩阵 matrix 中的一个目标值 target.该矩阵具有以下特性: 每行的元素从左到右升序排列. 每列的元素从上到下升序排列. 示例: 现有矩阵 matrix 如下: [ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ] 给定 target = 5,返回 true. 给定 target = 2…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…

题意: 有一个矩阵,每行有序,每列也有序.判断一个数target是否存在于此矩阵中. 思路: 从右上角开始,如果当前数字<target,则该行作废.若当前数字>target,该列作废.这样下去要么找到,要么到达边界退出. class Solution { public: bool searchMatrix(vector<vector<int>>& matrix, int target) { ].size(); , j=m-; ) { if(target==mat…

[ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ] 观察,从左到右递增,从上到下递增.似乎找不到什么其他规律.第一想法是二分,笨方法. 感觉这个是有序数组求两个数的和为sum的扩展.巧妙啊!看了题解才会的. 观察左下角或者右下角的元素.所有比18大的,都在18右边.比18小的都在它上边. 只能感叹啊!什么时候能有这样的功力呢? bool se…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom.…