本文是在学习中的总结,欢迎转载但请注明出处:http://blog.csdn.net/pistolove/article/details/41851705 You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 思路: (1…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 这个爬梯子问题最开始看的时候没搞懂是让干啥的,后来看了别人的分析后,才知道实际上跟斐波那契数列非常相似,假设梯子有n层,那么如何爬到第n层呢,因为每次只能怕1或2步,那…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Have you met this question in a real interview? Yes Example Given an example n=3 , 1…

July 28, 2015 Problem statement: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? The problem is most popular question in the algorit…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example Given an example n=3 , 1+1+1=2+1=1+2=3 return 3 For the problem, try to thin…

Search a 2D Matrix Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer…

Climbing Stairs https://leetcode.com/problems/climbing-stairs/ You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 算法描述 (1)这道题其实是一道fibon…

原题 Climbing Stairs 求斐波那契数列的第N项,开始想用通项公式求解,其实一个O(n)就搞定了. class Solution { public: int climbStairs(int n) { ) ; ; ; ; i<n; ++i) { int t = n2; n2 = n1 + n2; n1 = t; } return n2; } }; 还是觉得没有ACM难度,继续做吧.…

1- 问题描述 You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 2- 思路分析 很自然的会想到递归,假设 n 级台阶有 T(n) 种不同走法.最后一步存在两种情况:剩下 1 级台阶,或者,剩下 2 级台阶. 第一种情…

Climbing Stairs  You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 思路:题目也比較简单.类似斐波那契. 代码例如以下: public class Solution { public int climb…

Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 题目意思: 上楼梯.假设要n步到达楼梯的顶部.每一次你只能上一个或两级台阶,问要到达顶部一共有多少种方法? 解题思路: 真是太巧了!!我…

70. Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. 思路:到第n个台阶的迈法种数＝到第n-1个台…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

题目描述 假设你正在爬楼梯.需要 n 阶你才能到达楼顶. 每次你可以爬 1 或 2 个台阶.你有多少种不同的方法可以爬到楼顶呢? 注意:给定 n 是一个正整数. 示例 1: 输入: 2 输出: 2 解释: 有两种方法可以爬到楼顶. 1. 1 阶 + 1 阶 2. 2 阶 示例 2: 输入: 3 输出: 3 解释: 有三种方法可以爬到楼顶. 1. 1 阶 + 1 阶 + 1 阶 2. 1 阶 + 2 阶 3. 2 阶 + 1 阶 思路 思路一: 递归 思路二: 用迭代的方法,用两个变量记录f(n-…

A. Dasha and Stairs 题目连接: http://codeforces.com/contest/761/problem/A Description On her way to programming school tiger Dasha faced her first test - a huge staircase! The steps were numbered from one to infinity. As we know, tigers are very fond of…

A. Dreamoon and Stairs 题目连接: http://www.codeforces.com/contest/476/problem/A Description Dreamoon wants to climb up a stair of n steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer m. What…

［抄题］: 假设你正在爬楼梯,需要n步你才能到达顶部.但每次你只能爬一步或者两步,你能有多少种不同的方法爬到楼顶部? ［思维问题］: 不知道一步.两步怎么加.还是用iteration迭代.此题公式可被称为斐波那契数列. 不知道和坐标型有什么关系:列j = 1即可 ［一句话思路］: 生兔子问题:把大数赋给小数 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: ［二刷］: ［三刷］: ［四刷］: ［五刷］: [五分钟肉眼debu…

A. Dasha and Stairs time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output On her way to programming school tiger Dasha faced her first test — a huge staircase! The steps were numbered from one t…

Climbing Stairs https://oj.leetcode.com/problems/climbing-stairs/ You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 这题比较简单,可以使用动态规划来求解…

目录 题目链接 注意点 解法 小结 题目链接 Min Cost Climbing Stairs - LeetCode 注意点 注意边界条件 解法 解法一:这道题也是一道dp题.dp[i]表示爬到第i层的最小cost,想要到达第i层只有两种可能性,一个是从第i-2层上直接跳上来,一个是从第i-1层上跳上来.所以可以得到dp[i] = min(dp[i- 2] + cost[i - 2], dp[i - 1] + cost[i - 1]).时间复杂度O(n). class Solution { pu…

目录 题目链接 注意点 解法 小结 题目链接 Climbing Stairs - LeetCode 注意点 注意边界条件 解法 解法一:这道题是一题非常经典的DP题(拥有非常明显的重叠子结构).爬到n阶台阶有两种方法:1. 从n-1阶爬上 2. 从n-2阶爬上.很容易得出递推式:f(n) = f(n-1)+f(n-2)于是可以得到下面这种最简单效率也最低的解法 -- 递归. class Solution { public: int climbStairs(int n) { if(n == 0 |…

Climbing Stairs 本题收获: 1.斐波那契函数f(n) = f(n-1) + f(n -2) 题目: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 有n阶台阶,每次可以走2步或者1步,问有多少种方法到…

A. Dreamoon and Stairs time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Dreamoon wants to climb up a stair of n steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of mo…

A. Dasha and Stairs time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output On her way to programming school tiger Dasha faced her first test - a huge staircase! The steps were numbered from one t…

Time Limit: 1sec    Memory Limit:32MB  Description John is moving to the penthouse of a tall sky-scraper. He packed all his stuff in boxes and drove them to the entrance of the building on the ground floor. Unfortunately the elevator is out of order,…

A. Dasha and Stairs time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output On her way to programming school tiger Dasha faced her first test — a huge staircase! The steps were numbered from one t…

back function (return number) remember the structure class Solution { int res = 0; //List<List<Integer>> resList = new ArrayList<List<Integer>>(); public int combinationSum4(int[] nums, int target) { Arrays.sort(nums); return back(…

http://codeforces.com/contest/476/problem/A A. Dreamoon and Stairs time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Dreamoon wants to climb up a stair of n steps. He can climb 1 or 2 steps a…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

lc 746 Min Cost Climbing Stairs 746 Min Cost Climbing Stairs On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach t…